A. I’m not positive but I’m pretty sure
Answer:
1. C = 0.73 M.
2. pH = 0.14
Explanation:
The reaction is the following:
HCl + NH₃ ⇄ NH₄⁺Cl⁻
From the titration, we can find the number of moles of HCl that were neutralized by the ammonia.

Where "a" is for acid and "b" is for base.
The number of moles is:
Where "C" is for concentration and "V" for volume.


Hence the initial concentration of the acid is 0.73 M.
The original pH of the acid is given by:
![pH = -log([H^{+}])](https://tex.z-dn.net/?f=%20pH%20%3D%20-log%28%5BH%5E%7B%2B%7D%5D%29%20)
Therefore, the original pH of the acid is 0.14.
I hope it helps you!
Answer: 4.12
Explanation:
we know that the given mol is 8.23 mol and they are 2NaI and I2 so we will write the equation like this.
8.23mol NaI x 1mol of I2 ÷ 2molNaI = 4.115≅ 4.12 mol of I2
we placed NaI at the bottom to cancel out with the 8.23 mol of NaI
Its A. the energy is stored within the nuclear of the atom