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3 years ago

State one conclusion from Rutherford experiment that contradicted one conclusion made by Thompson

1 answer:

6 0

One conclusion from Rutherford's experiment that greatly contradicted Thompson's experiment is that 'atoms are mostly empty space, with positively charged nucleus'. While Thompson concluded that there are negatively charged particles as part of the internal structure of the atoms.

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What diffuses more quickly: tetracarbon decahydride (C4H10) or iodine (12)? By how much?

ValentinkaMS [17]

Answer: Butane will effuse more quickly because it has a smaller molar mass

Explanation:

Molar mass of C4H10 = 58.123 g/mole

Molar mass of I2 = 253.808 g/mole

5 0

3 years ago

A buffer consists of 0.120 M HNO2 and 0.150 M NaNO2 at 25°C. pka of HNO2 is 3.40. a. What is the pH of the buffer? b. What is th

Mashcka [7]

Explanation:

It is known that $K_{a}$ of $HNO_{2}$ = $4.5 \times 10^{-4}$ .

(a) Relation between $K_{a}$ and $pK_{a}$ is as follows.

$pK_{a} = -log (K_{a})$

Putting the values into the above formula as follows.

$pK_{a} = -log (K_{a})$

= $-log(4.5 \times 10^{-4})$

= 3.347

Also, relation between pH and $pK_{a}$ is as follows.

pH = $pK_{a} + log\frac{[conjugate base]}{[acid]}$

= $3.347+ log \frac{0.15}{0.12}$

= 3.44

Therefore, pH of the buffer is 3.44.

(b) No. of moles of HCl added = $Molarity \times volume$

= $11.6 M \times 0.001 L$

= 0.0116 mol

In the given reaction, $NO^{-}_{2}$ will react with $H^{+}$ to form $HNO_{2}$

Hence, before the reaction:

No. of moles of $NO^{-}_{2}$ = $0.15 M \times 1.0 L$

= 0.15 mol

And, no. of moles of $HNO_{2}$ = $0.12 M \times 1.0 L$

= 0.12 mol

On the other hand, after the reaction :

No. of moles of $NO^{-}_{2}$ = moles present initially - moles added

= (0.15 - 0.0116) mol

= 0.1384 mol

Moles of $HNO_{2}$ = moles present initially + moles added

= (0.12 + 0.0116) mol

= 0.1316 mol

As, $K_{a}$ = $4.5 \times 10^{-4}$

$pK_{a} = -log (K_{a})$

= $-log(4.5 \times 10^{-4})$

= 3.347

Since, volume is both in numerator and denominator, we can use mol instead of concentration.

As, pH = $pK_{a} + log \frac{[conjugate base]}{[acid]}$

= 3.347+ log {0.1384/0.1316}

= 3.369

= 3.37 (approx)

Thus, we can conclude that pH after the addition of 1.00 mL of 11.6 M HCl to 1.00 L of the buffer solution is 3.37.

6 0

3 years ago

Name for temperature for freezing

Debora [2.8K]

For water to freeze it would need to be 32 degrees Fahrenheit or 0 degrees Celsius.

5 0

3 years ago

There is a limited amount of matter on Earth.

riadik2000 [5.3K]

I'm not sure where the question is here. Yes it is true that there is a limited amount of matter on Earth...

8 0

4 years ago

Read 2 more answers

1. Adrian has a rectangular block with the dimensions 3.5 in by 8.0 in by 5.5

miskamm [114]

Answer:

The density of the block is 2.827 grams/ cubic inch

Explanation:

The density of the block can be obtained by dividing the given mass of the block by its volume.

Density = mass / volume

The mass of the block given is 435.5 grams

The volume of the block can be obtained by using the formula:

Volume = Length X breadth X height

Volume = 3.5 X 8 X 5.5 = 154 $in^3$

There fore the density will be 435.5 / 154 = 2.827 grams/ cubic inch

8 0

3 years ago