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3 years ago

Which of the following is an example of a constructive force?

Chemistry

1 answer:

Sliva [168]3 years ago

4 0

D, the lava from the volcano can reach water and make new land

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Two hydrogen nuclei repel one another due to the positive charges of the protons within them. At some separation distance this r

ValentinkaMS [17]

Answer: The answer to your question is D) Strong nuclear force

Explanation:

In nature, there are four fundamental interactions: electromagnetism, gravitation, weak nuclear force and strong nuclear force.

The Strong nuclear force is responsible for binding protons and neutrons to form a new nucleus.

Weak nuclear force is responsible for radioactive decay which means splitting nucleus.

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3 years ago

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What sound is produced when lithium react with water?

Arisa [49]

Answer:

lithium reacts with water, forming lithium hydroxide and highly flammable hydrogen

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3 years ago

Which statement describes the feeling interactions between frogs and insects? Select all that apply.

love history [14]

DO NoT OpEN The file it takes all you’re information and hacks into you’re device a lot of people are doing it on here be careful

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2 years ago

Crabs are organisms that have five pairs of legs. In certain species of crabs, the fifth pair of legs has a flattened, paddle-li

Katyanochek1 [597]

Answer:

Explanation:

Crabs were exposed to a toxin in the water.

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3 years ago

Consider the reaction N2(g) + 2O2(g)2NO2(g) Using standard thermodynamic data at 298K, calculate the entropy change for the surr

zysi [14]

<u>Answer:</u> The value of $\Delta S^o$ for the surrounding when given amount of nitrogen gas is reacted is 231.36 J/K

<u>Explanation:</u>

Entropy change is defined as the difference in entropy of all the product and the reactants each multiplied with their respective number of moles.

The equation used to calculate entropy change is of a reaction is:

$\Delta S^o_{rxn}=\sum [n\times \Delta S^o_{(product)}]-\sum [n\times \Delta S^o_{(reactant)}]$

For the given chemical reaction:

$N_2+2O_2\rightarrow 2NO_2$

The equation for the entropy change of the above reaction is:

$\Delta S^o_{rxn}=[(2\times \Delta S^o_{(NO_2(g))})]-[(1\times \Delta S^o_{(N_2(g))})+(2\times \Delta S^o_{(O_2(g))})]$

We are given:

$\Delta S^o_{(NO_2(g))}=240.06J/K.mol\\\Delta S^o_{(O_2)}=205.14J/K.mol\\\Delta S^o_{(N_2)}=191.61J/K.mol$

Putting values in above equation, we get:

$\Delta S^o_{rxn}=[(2\times (240.06))]-[(1\times (191.61))+(2\times (205.14))]\\\\\Delta S^o_{rxn}=-121.77J/K$

Entropy change of the surrounding = - (Entropy change of the system) = -(-121.77) J/K = 121.77 J/K

We are given:

Moles of nitrogen gas reacted = 1.90 moles

By Stoichiometry of the reaction:

When 1 mole of nitrogen gas is reacted, the entropy change of the surrounding will be 121.77 J/K

So, when 1.90 moles of nitrogen gas is reacted, the entropy change of the surrounding will be = $\frac{121.77}{1}\times 1.90=231.36 J/K$

Hence, the value of $\Delta S^o$ for the surrounding when given amount of nitrogen gas is reacted is 231.36 J/K

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3 years ago