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strojnjashka [21]
4 years ago
11

Bayside Insurance offers two health plans. Under plan A, Giselle

Mathematics
1 answer:
LiRa [457]4 years ago
4 0

Answer:

Step-by-step explanation:

Let x represent the amount of medical bills that Giselle has to pay.

Assume she has over $160 in bills,

it means that

x > 160

Under plan A, Giselle would have to pay the first $110 of her medical bills, plus 35% of the rest. Therefore, she will have to pay for

35/100 × (x - 110) = 0.35(x - 110)

Under plan B, Giselle would pay the first $160, but only 20% of the rest. Therefore, she will have to pay for

20/100 × (x - 160) = 0.2(x - 160)

Therefore, the amount of medical bills that plan B will save is

0.35(x - 110) - 0.2(x - 160) = 0.35x - 38.5 - 0.2x + 32

0.15x + 6.5

Substituting x = 160 into 0.15x + 6.5, it becomes

0.15 × 160 + 6.5 = $30.5

Total bills would be 160 + 30.5 = 190.5

Therefore, Giselle would save $30.5 with plan B if she had more than $190.5 in bills.

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A sock drawer contains eight navy blue socks and five black socks with no other socks. If you reach in the drawer and take two s
Rzqust [24]

Answer:

a. the probability of picking a navy sock and a black sock = P (A & B)

= (8/13 ) * (5/12) = 40/156 = 0.256

b. the probability of picking two navy or two black is

= 56/156 + 20/156 = 76/156 = 0.487

c. the probability of either 2 navy socks is picked or one black  & one navy socks.

= 40/156 + 56/156 = 96/156 = 0.615

Step-by-step explanation:

A sock drawer contains 8 navy blue socks and 5 black socks with no other socks.

If you reach in the drawer and take two socks without looking and without replacement, what is the probability that:  

Solution:

total socks = N = 8 + 5 + 0 = 13

a) you will pick a navy sock and a black sock?

Let A be the probability of picking a navy socks first.

Then P (A) = 8/13

without replacing the navy sock, will pick the black sock, total number of socks left is 12.

Let B be the probability of picking a black sock again.

 P (B) = 5/12.

Then, the probability of picking a navy sock and a black sock = P (A & B)

= (8/13 ) * (5/12) = 40/156 = 0.256

b) the colors of the two socks will match?

Let A be the probability of picking a navy socks first.

Then P (A) = 8/13

without replacing the navy sock, will pick another navy sock, total number of socks left is 12.

Let B be the probability of another navy sock again.

 P (B) = 7/12.

Then, the probability of picking 2 navy sock = P (A & B)

= (8/13 ) * (7/12) = 56/156 = 0.359

Let D be the probability of picking a black socks first.

Then P (D) = 5/13

without replacing the black sock, will pick another black sock, total number of socks left is 12.

Let E be the probability of another black sock again.

 P (E) = 4/12.

Then, the probability of picking 2 black sock = P (D & E)

= (5/13 ) * (4/12) = 5/39 = 0.128

Now, the probability of picking two navy or two black is

= 56/156 + 20/156 = 76/156 = 0.487

c) at least one navy sock will be selected?

this means, is either you pick one navy sock and one black or two navy socks.

so, if you will pick a navy sock and a black sock, the probability of picking a navy sock and a black sock = P (A & B)

= (8/13 ) * (5/12) = 40/156 = 0.256

also, if you will pick 2 navy sock, Then, the probability of picking 2 navy sock = P (A & B)

= (8/13 ) * (7/12) = 56/156 = 0.359

now either 2 navy socks is picked or one black  one navy socks.

= 40/156 + 56/156 = 96/156 = 0.615

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Celsius, Fahrenheit, Kelvin? One’d colder than the other. Unless ur looking for a detailed answer lol.
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