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viva [34]
3 years ago
12

The potential energy of a catapult was completely converted into kinetic energy by releasing a small stone with a mass of 20 gra

ms. The velocity of the stone when it reached the target was 15.0 meters/second. What was the value of the kinetic energy of the stone when it reached the target?
Physics
2 answers:
vaieri [72.5K]3 years ago
6 0

Answer: 2.25 J

Explanation: Kinetic energy is the energy possessed by an object by virtue of its motion.

K.E=\frac{1}{2}\times mv^2

m= mass of object= 20 g = 0.02 kg     (1 kg= 1000 g)

v= velocity of object= 15 m/s

K.E=\frac{1}{2}\times 0.02\times 15^2=2.25kgm^2s^{-2}=2.25J

(1J=1kgm^2s^{-2})

DerKrebs [107]3 years ago
4 0

1,000 grams = 1 kilogram
20 grams = 0.02 kilogram

Kinetic energy = (1/2) (mass) x (speed)²

                           (1/2) (0.02) x (15)² =

                                 (0.01)  x  (225)  =  2.25 joules
 
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Svetradugi [14.3K]

Hello. This question is incomplete. The full question is:

A conducting sphere contains positive charge distributed uniformly over its surface. Which statements about the potential due to this sphere are true? All potentials are measured relative to infinity. (There may be more than one correct choice.)

A) The potential is lowest, but not zero, at the center of the sphere.  B) The potential at the center of the sphere is zero.  C) The potential at the center of the sphere is the same as the potential at the surface.  D) The potential at the surface is higher than the potential at the center.  E) The potential at the center is the same as the potential at infinity

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