Answer:
The speed of James is 0.776 m/s
Explanation:
Step 1: Data given
mass of James = 95.0 kg
mass of Ramon = 67.0 kg
We consider James and Ramon and the rope to a single system. This means that the net external forces on the system = 0
.The momentum = 0, so the sum of the momentum of each part must be 0 in total.
Step 2: Calculate the speed of James
m(james) *v(James) = m(Ramon) * v(Ramon)
with m(James) = the mass of James = 95.0 kg
with v(James) = speed of James = TO BE DETERMINED
with m(Ramon) = mass of Ramon = 67.0 kg
with v(Ramon) = speed of Ramon = 1.10 m/s
v(James) = (m(Ramon) * v(Ramon))/ m(james)
v(James) = (67.0 kg* 1.10 m/s) / 95.0 kg
v(James) = 0.776 m/s
The speed of James is 0.776 m/s
Answer:
0.256 hours
Explanation:
<u>Vectors in the plane
</u>
We know Office A is walking at 5 mph directly south. Let
be its distance. In t hours he has walked

Office B is walking at 6 mph directly west. In t hours his distance is

Since both directions are 90 degrees apart, the distance between them is the hypotenuse of a triangle which sides are the distances of each office



This distance is known to be 2 miles, so


t is approximately 15 minutes