A chemist has three different acid solutions. The first acid solution contains 25%

HELP ASAP!<br> Show your work also

vampirchik [111]

For the square part- 10*10=100sq in

For the half circle
r=5
5*5=25
3.14*25=78.5

5 0

3 years ago

Help please explain how you got the answer

pychu [463]

Answer: V≈900 ft³

Step-by-step explanation:

Formula

V=πr²h

Given

r=5 ft

h=12 ft

Solve

V=πr²h

V=π(5)²(12)

V=π(25)(12)

V=300π

V≈300(3)

V≈900 ft³

Hope this helps!! :)

Please let me know if you have any questions

5 0

3 years ago

A professor would like to test the hypothesis that the average number of minutes that a student needs to complete a statistics e

professor190 [17]

Answer:

$\chi^2 =\frac{15-1}{25} 16 =8.96$

The degrees of freedom are given by:

$df = n-1 = 15-1=14$

The p value for this case would be given by:

$p_v =P(\chi^2$

Since the p value is higher than the significance level we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviation is not ignificantly lower than 5 minutes

Step-by-step explanation:

Information given

$n=15$ represent the sample size

$\alpha=0.05$ represent the confidence level

$s^2 =16$ represent the sample variance

$\sigma^2_0 =25$ represent the value that we want to verify

System of hypothesis

We want to test if the true deviation for this case is lesss than 5minutes, so the system of hypothesis would be:

Null Hypothesis: $\sigma^2 \geq 25$

Alternative hypothesis: $\sigma^2$

The statistic is given by:

$\chi^2 =\frac{n-1}{\sigma^2_0} s^2$

And replacing we got:

$\chi^2 =\frac{15-1}{25} 16 =8.96$

The degrees of freedom are given by:

$df = n-1 = 15-1=14$

The p value for this case would be given by:

$p_v =P(\chi^2$

Since the p value is higher than the significance level we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviation is not ignificantly lower than 5 minutes

6 0

3 years ago

Cards with the numbers 1 through 40 are placed in a box and thoroughly shuffled.

MrRa [10]

9/40 + 2/40 = 11/40

hope this helps

7 0

3 years ago

Help me plsss! Thank you

Brrunno [24]

You want to calculate the interest on $3020 at 5% interest per year after 6 6 month period(s).

The formula we'll use for this is the simple interest formula, or:

Where:

P is the principal amount, $3020.00.

r is the interest rate, 5% per year, or in decimal form, 5/100=0.05.

t is the time involved, 6....6 month period(s) time periods.

Since your interest rate is "per year" and you gave your time interval in "6 month period(s)" we need to convert your time interval into "year" as well.

Do this by dividing your time, 6- 6 month period(s), by two (2), since there's two 6-month periods in 1 year.

So, t is 3....year time periods.

To find the simple interest, we multiply 3020 × 0.05 × 3 to get that:

The interest is: $453.00

Usually now, the interest is added onto the principal to figure some new amount after 6 6 month period(s),

or 3020.00 + 453.00 = 3473.00. For example:

If you borrowed the $3020.00, you would now owe $3473.00

If you loaned someone $3020.00, you would now be due $3473.00

If owned something, like a $3020.00 bond, it would be worth $3473.00 now.

4 0

3 years ago

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