PLEASEEE HELPPP MEEE WITH NUMBERSSSS 9 AND 10 QUESTION: Find the measure of each numbered angle
2 answers:
You might be interested in
Answer:
Null hypothesis:
Alternative hypothesis:
So we need to conduct a:
D. A two-sample z-test for a difference in population proportions
Because the idea is to check if the population proportions in the states are similar or not.
Step-by-step explanation:
For this case they are trying two proof if there is a significant difference between two states in the percents of high school students who order yearbooks, and we chan check this with the difference of proportions.
Lets say that are the two proportions of interest and we want to check the following hypothesis:
We have the following info given:
proportion of students that had ordered a yearbook from one state
proportion of students that had ordered a yearbook from another state
sample size from one state
sample size from another state
Null hypothesis:
Alternative hypothesis:
So we need to conduct a:
D. A two-sample z-test for a difference in population proportions
Because the idea is to check if the population proportions in the states are similar or not.
Answer:
97.5% of newborn babies born in the maternity wing of this hospital can be expected to have birth weight greater than 2250 grams.
Step-by-step explanation:
The Empirical Rule states that, for a normally distributed random variable:
Approximately 68% of the measures are within 1 standard deviation of the mean.
Approximately 95% of the measures are within 2 standard deviations of the mean.
Approximately 99.7% of the measures are within 3 standard deviations of the mean.
The normal distribution is symmetric, which means that 50% of the values are below the mean and 50% are above.
In this problem, we have that:
Mean of 3300, standard deviation of 525.
What percent of newborn babies born in the maternity wing of this hospital can be expected to have birth weight greater than 2250 grams?
2250 = 3300 - 2*525
2250 is 2 standard deviations below the mean.
Of the 50% of the weights below the mean, 95% are going to be greater than 2250(less than 2 standard deviations of the mean).
Of the 50% of the weights above the mean, 100% are going to be greater than 2250.
So
0.975*100% = 97.5%
97.5% of newborn babies born in the maternity wing of this hospital can be expected to have birth weight greater than 2250 grams.