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3 years ago

Which type of radiation has neither mass nor charge?

Chemistry

2 answers:

Lelu [443]3 years ago

5 0

A .gamma

Because composed of photons, which have neither mass nor electric charge and, as a result, penetrates much further through matter than either alpha or beta radiation.

Sati [7]3 years ago

3 0

The type of radiation is gamma

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Titanium has an HCP crystal structure, a c/a ratio of 1.669, an atomic weight of 47.87 g/mol, and a density of 4.51 g/cm3. Compu

IrinaK [193]

Answer : The atomic radius for Ti is, $1.45\times 10^{-8}cm$

Explanation :

Atomic weight = 47.87 g/mole

Avogadro's number $(N_{A})=6.022\times 10^{23} mol^{-1}$

First we have to calculate the volume of HCP crystal structure.

Formula used :

$\rho=\frac{Z\times M}{N_{A}\times V}$ .............(1)

where,

$\rho$ = density = $4.51g/cm^3$

Z = number of atom in unit cell (for HCP = 6)

M = atomic mass = 47.87 g/mole

$(N_{A})$ = Avogadro's number

V = volume of HCP crystal structure = ?

Now put all the values in above formula (1), we get

$4.51g/cm^3=\frac{6\times (47.87g/mol)}{(6.022\times 10^{23}mol^{-1}) \times V}$

$V=1.06\times 10^{-22}cm^3$

Now we have to calculate the atomic radius for Ti.

Formula used :

$V=6R^2c\sqrt{3}$

Given:

c/a ratio = 1.669 that means, c = 1.669 a

Now put (c = 1.669 a) and (a = 2R) in this formula, we get:

$V=6R^2\times (1.669a)\sqrt{3}$

$V=6R^2\times (1.669\times 2R)\sqrt{3}$

$V=(1.669)\times (12\sqrt{3})R^3$

Now put all the given values in this formula, we get:

$1.06\times 10^{-22}cm^3=(1.669)\times (12\sqrt{3})R^3$

$R=1.45\times 10^{-8}cm$

Therefore, the atomic radius for Ti is, $1.45\times 10^{-8}cm$

3 0

3 years ago

I have no idea what I'm doing in chemistry please help.

Tresset [83]

Your just answering the questions..? lol

5 0

3 years ago

After a wire and filament have been connected, the second requirement for the conduction of electricity is a(n) _____. conductiv

Mrac [35]

energy source

Explanation:

After wire and filament have been connected, for the conduction of electricity, an energy source is required.

In the energy source, electrical energy is produced.

The energy source can be a simple electrochemical cell.
It can be a generator.
It can also be current from the national grid.
The energy source produces current which is carried in wire and it powers the filament

Learn more:

Metals as conductors brainly.com/question/2474874

#learnwithBrainly

3 0

3 years ago

Read 2 more answers

How many milliliters of a 6.00 M NaCl solution are needed to make 250.0 milliliters of a 0.500 M NaCl solution?

kenny6666 [7]

Answer:

20,8ml NaCl 6M

Explanation:

C1V1 = C2V2

4 0

3 years ago

Write a balanced half-reaction for the reduction of gaseous oxygen to aqueous hydrogen peroxide in basic aqueous solution. Be su

Vesna [10]

Answer:

Balanced half-reaction: $O_{2}(g)+2H_{2}O(l)+2e^{-}\rightarrow H_{2}O_{2}(aq.)+2OH^{-}(aq.)$

Explanation:

Balanced half-reaction for the reduction of gaseous oxygen to aqueous hydrogen peroxide in basic solution should be written in the following step-by-step manner:

Half-reaction: $O_{2}(g)\rightarrow H_{2}O_{2}(aq.)$

Balance H and O in basic medium: $O_{2}(g)+2H_{2}O(l)\rightarrow H_{2}O_{2}(aq.)+2OH^{-}(aq.)$

Balance charge: $O_{2}(g)+2H_{2}O(l)+2e^{-}\rightarrow H_{2}O_{2}(aq.)+2OH^{-}(aq.)$

Balanced half-reaction: $O_{2}(g)+2H_{2}O(l)+2e^{-}\rightarrow H_{2}O_{2}(aq.)+2OH^{-}(aq.)$

7 0

4 years ago