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3 years ago

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10 terminologias de educacion fisica con su definicion

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arlik [135]3 years ago

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Google it ******** *********

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SynthesizeWrite the instructions you would give a classmate to locate the point 27°18'N, 19°2'E on a globe.

SVEN [57.7K]

Answer:

<em>It is known by almost everyone Earth is divided into longitudes and latitudes which are imaginary lines that cut Earth into 2 equal parts.</em>

Explanation:

The main use of dividing Earth into so many imaginary lines is to know no of places perfect location in numbers. Direction and tell tales can make the place talked about a bit confusing but the exact longitudes and latitudes known pill and someone in exact position.

So in the positions given the question 27 ° and 19 ° show the distance of longitude from Prime Meridian While 18 ° and two degrees show the distance from the equator.

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3 years ago

What is an example of a physical change involving iron?

tatiyna

Melting iron would be a physical change

Iron rusting would be a chemical change

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3 years ago

Read 2 more answers

Balanced the equation please Fe + O2 → Fe2O3

kondor19780726 [428]

Answer: The balanced equation is 4,3,2,

Answer: Balanced equation = 4Fe + 3O2 => 2Fe2O3.

Explanation:

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3 years ago

A sample of brass is put into a calorimeter (see sketch at right) that contains of water. The brass sample starts off at and the

Ierofanga [76]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The specific heat is $c_b = 0.402 J / g \cdot ^oC$

Explanation:

From the question we are told that

The mass of the sample is $m = 54.4 \ g$

The mass of the water is $m_w = 150.0 \ g$

The initial temperature of the sample is $T_i = 95.1 ^oC$

The initial temperature of the water is $T_{w_i} = 15^oC$

The final temperature of the water is $T = 17.6 ^oC$

Note the final temperature of water is equal to the final temperature of brass sample

The pressure is $P =1 \ atm$

Generally for according to the law of energy conservation

The heat lost by sample = The heat gain by water

The heat lost by brass sample is mathematically evaluated as

$H_L = m * c_b * [T_i - T]$

Where $c_b$ is the specific neat of the brass sample

The heat gained by water is mathematically evaluated as

$H_g = m_w *c_w * [T_w - T ]$

where $c_w$ is the specific heat of water which has a constant value of

$c_w = 4.186 joule/gram$

So

$H_L = H_g \ \equiv m* c_b * [T_i -T] = m_w * c_w * [T - T_w]$

substituting values

$52.4 * c_b * [95.1 - 17.6] = 150 * 4.186 * [ 17.6 - 15.0]$

$c_b = 0.402 J / g \cdot ^oC$

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4 years ago

Tại sao dung dịch nacl dẫn điện

Margaret [11]

Tai said dung such nacl dân dên
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3 years ago