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slega [8]
3 years ago
11

Name two compounds in unpolluted air?

Chemistry
1 answer:
goblinko [34]3 years ago
6 0
Nitrogen and oxygen are in unpolluted air

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Write the empirical formula of at least four binary ionic compounds that could be formed from the following ions: ,
Serga [27]
Bynari means that the compound is formed by two kind of elements.

You have listed three ions, V 5+, Cl - and O 2-.

Binary ionic compounds are formed by a positive ion and a negative ion, so the possible ionic compound formed by the listed ions are:

1) VCl5, where the number 5 next to Cl is a subscript.

2) V2O5, where the number 2 next to V and the number 5 next to O are subscripts.

Subscripts are used to indicate the number of atoms of each element in the formula.

So, the empirical formula searched are VCl5 and V2O5.

I can give you other examples with more ions.

Ca (2+) and S(2-) => Ca2S2 => CaS

Na(+) and F(-) => NaF

Cs(+) and Br(-) => CsBr


6 0
3 years ago
What two aspects of a force do scientists measure?
soldier1979 [14.2K]

Yo sup??

Force is a vector quantity therefore it has both direction and magnitude.

Hence scientists measure magnitude and direction of a force.

Correct answer is option A

Hope this helps

5 0
3 years ago
Substance in which two or more elements are combined in a fixed proportion
Firdavs [7]

Answer: compound

Explanation:

Element is a pure substance which is composed of atoms of similar elements.It can not be decomposed into simpler constituents using chemical reactions.Example: Copper Cu

Compound is a pure substance which is made from atoms of different elements combined together in a fixed ratio by mass.It can be decomposed into simpler constituents using chemical reactions. Example: water H_2O

Mixture is a substance which has two or more components which do not combine chemically and do not have any fixed ratio in which they are present. Example: Air

8 0
3 years ago
A 0.5438 g of a C.H.O. compound was combusted in air to make 1.039 g of CO2 and 0.6369 g H20. What is the empirical formula? Bal
goblinko [34]

Answer:

C₃H₅O₂

4C₃H₅O₂ + 13O₂ → 12CO₂ + 10H₂O

Explanation:

The reaction can be expressed as:

CₓHₓOₓ + nO₂ → CO₂ + H₂O

Under the assumption that there was a total combustion, all of the carbon in the reactant was combusted into CO₂, so <u>the mass of C contained in the C.H.O. compound is the same mass of C contained in 1.039 g of CO₂</u>:

1.039gCO_{2}*\frac{1molCO_{2}}{44gCO_{2}} *\frac{1molC}{1molCO_{2}} *\frac{12gC}{1molC} =0.2834gC

All of the hydrogens atoms in the compound ended up becoming H₂O, so <u>the mass of H contained in the C.H.O. compound is the same mass of H contained in 0.6369 g of H₂O</u>:

0.6369g*\frac{1molH_{2}O}{18gH_{2}O} *\frac{1molH}{1molH_{2}O} *\frac{1gH}{1molH} =0.0354gH

Because the compound is composed only by C, H and O, <u>the mass of O in the compound can be calculated by substraction</u>:

0.5438 g Compound - 0.2834 g C - 0.0354 g H = 0.2250 g O

In order to determine the empirical formula, we calculate the moles of each component:

  • mol C = 0.2834 g C ÷ 12 g/mol = 0.0236 mol C
  • mol H = 0.0354 g H ÷ 1 g/mol = 0.0354 mol H
  • mol O = 0.2250 g O ÷ 16 g/mol = 0.0141 mol O

Then we divide those values by the lowest one:

0.0236 mol C ÷ 0.0141 = 1.67

0.0354 mol H ÷ 0.0141 = 2.51

0.0141 mol O ÷ 0.0141 = 1

If we multiply those values by 2, we're left with the empirical formula C₃H₅O₂.

  • The reaction is:

4C₃H₅O₂ + 13O₂ → 12CO₂ + 10H₂O

8 0
3 years ago
2. Hydrogen gas at a temperature of 22.0°C that is confined in a 5.00L cylinder exerts a pressure of 4.20atm. If the gas is rele
Umnica [9.8K]

Answer: n∗R=22+273.15/4.2∗5n

P2=n∗R∗T2/V2=n∗R∗33.6+273.15/10

Explanation:

4 0
3 years ago
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