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Gre4nikov [31]
3 years ago
7

Given two lines in​ space, either they are​ parallel, they​ intersect, or they are skew​ (lie in parallel​ planes). determine wh

ether the lines​ below, taken two at a​ time, are​ parallel, intersect, or are skew. if they​ intersect, find the point of intersection.​ otherwise, find the distance between the two lines.
Mathematics
1 answer:
Naddika [18.5K]3 years ago
8 0
I believe by intersect, you mean perpendicular. Also, skew lines can be on parallel planes and still intersect. If they intersected, then the degrees must be 90
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URGENT!!! I NEED HELP ON THIS PLSSSS!!! IT'S DUE IN LIKE 3 hOURS!!!!!
Nataly_w [17]

Answer:

For number 3 your answer would be the second function.  

I hope this helps a little bit!

5 0
3 years ago
Read 2 more answers
If the typical balance on Lucy's credit card is $650 and the interest rate (APR) on her credit card is 18%, how much in interest
Mariana [72]

$9.75

<h3>Further explanation   </h3>

Given:  

  • The typical balance on Lucy's credit card is $650.
  • The interest rate (APR) on her credit card is 18%.

Question:  

How much in interest would you expect Lucy to be charged in a typical month?

The Process:  

This problem includes the type of determining simple interest.

\boxed{ \ I = P \times r \times t \ }  

where,

  • I = simple interest
  • P = principal (initial amount)  
  • r = annual interest rate
  • t = time (in years)

This time we will find out how much in interest we would expect to be charged in a typical month.

The data is as follows:

  • P = 650
  • r = 18% or \frac{18}{100} or 0.18  
  • t = \frac{1}{12} year  (one month)

Let us calculate how much in interest we would expect to be charged in a typical month.

\boxed{ \ = 650 \times \frac{18}{100} \times \frac{1}{12} \ }  

\boxed{ \ = 65 \times \frac{3}{10} \times \frac{1}{2} \ }  

\boxed{ \ = \frac{195}{10} \times \frac{1}{2} \ }  

\boxed{ \ = \frac{97.5}{10} \ }  

\boxed{ \ = \frac{975}{100} \ }  

Thus the amount of interest we would expect Lucy to be charged in a typical month is $ 9.75.

_ _ _ _ _ _ _ _ _ _

Notes  

We must be able to distinguish between simple and compound interest. Please learn about this in the link attached below.

<h3>Learn more   </h3>
  1. What interest (in dollars) does he receive annually?  brainly.com/question/8192969    
  2. How much will our account accrue to in 9.5 years brainly.com/question/4127036  
  3. What is the total amount owed at the end of the 4 years brainly.com/question/13675435
4 0
3 years ago
Read 2 more answers
SOMEONE PLS HELP ME I WILL MAKE U BRAINLIST ! In a survey sample of 83 respondents, about 30.1 percent of the samplework less th
nignag [31]

Answer:

Answer = √(0.301 × 0.699 / 83) ≈ 0.050

A 68 percent confidence interval for the proportion of persons who work less than 40 hours per week is (0.251, 0.351), or equivalently (25.1%, 35.1%)

Step-by-step explanation:

√(0.301 × 0.699 / 83) ≈ 0.050

We have a large sample size of n = 83 respondents. Let p be the true proportion of persons who work less than 40 hours per week. A point estimate of p is  because about 30.1 percent of the sample work less than 40 hours per week. We can estimate the standard deviation of  as . A  confidence interval is given by , then, a 68% confidence interval is , i.e., , i.e., (0.251, 0.351).  is the value that satisfies that there is an area of 0.16 above this and under the standard normal curve.The standard error for a proportion is √(pq/n), where q=1−p.

Hope this answer helps you :)

Have a great day

Mark brainliest

6 0
3 years ago
bob needs to be at school by 7:00 it takes him 1 hour and 21 minutes to get there. his morning routine takes 30 minutes. what ti
Maslowich
He should leave at 6:39
4 0
3 years ago
building across the street casts a shadow that is 24 feet long. Your friend is 6 feet tall and casts a shadow that is 4 feet lon
atroni [7]

Answer:

6/4=b/24

1.5=b/24

24(1.5)=b

36=b

Building is 36 ft tall

Step-by-step explanation:

3 0
3 years ago
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