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3 years ago

10

A bag of marbles contains 3 red marbles, 4 blue marbles, and 6 green marbles. If two marbles are pulled out without replacement,

find the probability of getting one red and one blue marble.
(Can you show the work so I can see how to get the answer) thanks.

1 answer:

Whitepunk [10]3 years ago

5 0

3+4+6=13

2/13 should be the answer. i am not sure

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Question 2 (essay worth 10 points)

Sliva [168]

The sample space for the arrangement of a jazz CD (J), a pop CD (P), and a rock CD (R) is {JPR, JRP, PJR, PRJ, RJP, RPJ}.

<h3>What is permutation and combination?</h3>

A permutation is the number of different ways a set can be organized; order matters in permutations, but not in combinations.

We have:

Minni is arranging 3 different music CDs in a row on a shelf.

Three CDs are a jazz cd (j), a pop cd (p), and a rock cd (r).

The sample space means all the possible ways to arrange the CDs.

Total arramgement = 3! = 3×2×1 = 6

The sample space for the arrangement of a jazz CD (J), a pop CD (P), and a rock CD (R) is:

{JPR, JRP, PJR, PRJ, RJP, RPJ}

Thus, the sample space for the arrangement of a jazz CD (J), a pop CD (P), and a rock CD (R) is {JPR, JRP, PJR, PRJ, RJP, RPJ}.

Learn more about permutation and combination here:

brainly.com/question/2295036

#SPJ1

4 0

2 years ago

. The mean width of 12 iPads is 5.1 inches. The mean width of 8 Kindles is 4.8 inches. a. What is the total width of the iPads?

UkoKoshka [18]

Answer:

a) 61.2, b) 38.4 and c) 4.98

Step-by-step explanation:

Given:

The mean width of 12 I-Pads is 5.1 inches.

The mean width of 8 Kindles is 4.8 inches.

Question asked:

a. What is the total width of the I-Pads?

b. What is the total width of the Kindles?

c. What is the mean width of the 12 I-Pads and 8 Kindles?

Solution:

<u>As we know:</u>

<u /> $Mean =\frac{Sum\ of\ observations}{Number\ of\ observations}\\ \\ Mean\ width =\frac{Sum\ of\ width\ of\ all \ I-pad}{Number \ of\ I-pad}$

$5.1=\frac{Sum\ of\ width\ of\ all\ I-pad}{12} \\ \\ By \ cross\ multiplication\\ \\ Sum\ of\ width\ of\ all\ I-pad}=5.1\times1 2\\ \\ Sum\ of\ width\ of\ all\ I-pad}= 61.2$

a) Thus, the total width of the I-Pads are 61.2 inches.

$Mean\ width =\frac{Sum\ of\ width\ of\ all\ Kindles}{Number \ of\ Kindles}$

$4.8=\frac{Sum\ of\ width\ of\ all\Kindles}{8} \\ \\ By \ cross\ multiplication\\ \\ Sum\ of\ width\ of\ all \ Kindles=4.8\times8\\ \\ Sum\ of\ width\ of \ all\ Kindles}=38.4$

b) Thus, total width of the Kindles are 38.4 inches.

Combined width of both I-pad and Kindles = 61.2 + 38.4 = 99.6 inches

Combined number of observations = 12 + 8 =20

Combined mean of width of the 12 I-Pads and 8 Kindles = Combined width of both I-pad and Kindles $\div$ Combined number of observations

Combined mean of width of the 12 I-Pads and 8 Kindles = $\frac{99.6}{20} =4.98\ inches$

c) Thus, the mean width of the 12 I-Pads and 8 Kindles is 4.98 inches.

5 0

3 years ago

The perimeter of the triangle is 34 cm. Solve for x.

Musya8 [376]

5x-2+x-3+x-3 = 34
7x-8 = 34
7x/7 = 42/7
x = 6

3 0

3 years ago

Read 2 more answers

Really stuck here!! Which of the following equations has no real solutions?

borishaifa [10]

Answer:

D

Step-by-step explanation:

3 0

4 years ago

In the diagram m angle ACB = 61<br> Find m angle BCD

Marina86 [1]

we are given that

angle(ACF)=90

angle(ACB)=61

sum of all angles along any line is 180

so, we get

angle(ACF)+angle(ACD)=180

we can plug value

90+angle(ACD)=180

angle(ACD)=90

now, we can use formula

angle(ACD)=angle(ACB)+angle(BCD)

now, we can plug values

and we get

90=61+angle(BCD)

90-61=61-61+angle(BCD)

angle(BCD)=29................Answer

7 0

3 years ago

Read 2 more answers