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Ugo [173]
3 years ago
11

An individual who practices martial arts two hours a day for four weeks before fighting in a tournament is demonstrating which p

hase of the self-regulation cycle?
A.
self-reflection
B.
performance
C.
forethought
D.
goal accomplishment
Biology
2 answers:
Charra [1.4K]3 years ago
7 0

I'm pretty sure the answer is B. performance for anyone who still needs this :)

Natalija [7]3 years ago
5 0

The right option is; B. performance

The performance phase of the self-regulation cycle is the actual learning phase in which the actual task is performed. During this phase, specific strategies that can help the learner become more successful is utilized. Learning is made through the self-control process which is combined with self-monitoring in order to redevelop the learning strategy and to improve the performance.


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Como resultado del proceso de la fotosíntesis se elimina a través de los estomas a La glucosa b) El oxígeno. C) El dióxido de ca
Julli [10]

Answer:

Como resultado del proceso de la fotosíntesis se elimina a través de los estomas el oxígeno.

Explanation:

La fotosíntesis es un proceso metabólico que llevan a cabo determinadas células de organismos autótrofos, es decir, aquellas que tienen la capacidad de producir su propio alimento, como las plantas. Con este proceso, las plantas captan la energía de la luz solar y la transforman en energía química, para producir materia orgánica a través de materia inorgánica.

Los procesos que llevan a cabo las plantas en la fotosíntesis se llevan a cabo en 2 etapas: en la primera etapa las plantas absorben el agua del suelo a través de las raíces. A través de sus tallos lo transportan hasta sus hojas. En estos se encuentra el pigmento llamado clorofila, que además de darle a la hoja el color verde, capta la luz solar y rompe la molécula de agua (H₂O), separando el hidrógeno (H) del oxígeno (O₂). En esta etapa se almacena energía y se libera oxígeno al medio ambiente.

La otra etapa es capturar dióxido de carbono. Esto proporciona los átomos de carbono y oxígeno que, junto con el hidrógeno y la energía almacenada, formarán la molécula de glucosa.

Entonces, los estomas son poros en la superficie de las plantas, encontrándose mayoritariamente en las hojas y en menor medida en los tallos y otros órganos. En ellas transcurre el intercambio gaseoso mecánico, es decir que en este lugar sale el oxígeno y entra dióxido de carbono en la fotosíntesis.

Por lo que,<u><em> como resultado del proceso de la fotosíntesis se elimina a través de los estomas el oxígeno.</em></u>

5 0
3 years ago
In a population of 100 individuals, 50 are genotype MM, 40 are MN, and 10 are NN. What are the frequencies of the M and N allele
mrs_skeptik [129]

Answer:

F(M) = 0.7 F(N)=0.3

Explanation:

We need to take into account that individuals NN and MM only N or M aleles respectively while MN gives just half of the allelic contribution for each. With this in mind we have the following probabilities for getting each of the alleles: MM => p(M) = 1.0 and p(N)=0.0

MN => p(M ) = 0.5 and p(N) = 0.5

NN => P(M) = 0.0 and p(N) = 1.0

With this we can calculate the frequencies of the M and N alleles in the population with 100 individuals using the following formulas

For f(M):

f(M)=\frac{1.0 (MM) + 0.5 (MN)}{Total individuals}

f(M)=\frac{1.0(50)+0.5(40)}{100}

f(M) = \frac{50+20}{100}

f(M)=\frac{70}{100}=\frac{7}{10}=0.7

The frequency of the M allele is 0.7

For f(N):

f(N)=\frac{1.0 (NN) + 0.5 (MN)}{Total individuals}

f(N)=\frac{1.0(10)+0.5(40)}{100}

f(N) = \frac{10+20}{100}

f(M)=\frac{30}{100}=\frac{3}{10}=0.3

The frequency of the N allele is 0.3

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Answer:

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Explanation:

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