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3 years ago

What is shown in the diagram? A). A turbine B). An electromagnet C). A motor D). A generator

Physics

1 answer:

AlexFokin [52]3 years ago

4 0

Answer:

I just answered a question like this. It should be B. An electromagnet :)

Explanation:

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A boat radioed a distress call to a Coast Guard station. At the time of the call, a vector A from the station to the boat had a

VashaNatasha [74]

Answer:

d = 39.7 km

Explanation:

initial position of the boat is 45 km away at an angle of 15 degree East of North

so we will have

$r_1 = 45 sin15 \hat i + 45 cos15 \hat j$

$r_1 = 11.64 \hat i + 43.46\hat j$

after some time the final position of the boat is found at 30 km at 15 Degree North of East

so we have

$r_2 = 30 cos15\hat i + 30 sin15 \hat j$

$r_2 = 28.98\hat i + 7.76 \hat j$

now the displacement of the boat is given as

$d = r_2 - r_1$

$d = (28.98\hat i + 7.76 \hat j) - (11.64 \hat i + 43.46\hat j)$

$d = 17.34 \hat i - 35.7 \hat j$

so the magnitude is given as

$d = \sqrt{17.34^2 + 35.7^2}$

$d = 39.7 km$

4 0

3 years ago

Replacing an object attached to a spring with an object having 14 the original mass will change the frequency of oscillation of

Pachacha [2.7K]

Answer:

<em>The frequency changes by a factor of 0.27.</em>

Explanation:

The frequency of an object with mass m attached to a spring is given as

$f$ = $\frac{1}{2\pi } \sqrt{\frac{k}{m} }$

where $f$ is the frequency

k is the spring constant of the spring

m is the mass of the substance on the spring.

If the mass of the system is increased by 14 means the new frequency becomes

$f_{n}$ = $\frac{1}{2\pi } \sqrt{\frac{k}{14m} }$

simplifying, we have

$f_{n}$ = $\frac{1}{2\pi \sqrt{14} } \sqrt{\frac{k}{m} }$

$f_{n}$ = $\frac{1}{3.742*2\pi } \sqrt{\frac{k}{m} }$

if we divide this final frequency by the original frequency, we'll have

==> $\frac{1}{3.742*2\pi } \sqrt{\frac{k}{m} }$ ÷ $\frac{1}{2\pi } \sqrt{\frac{k}{m} }$

==> $\frac{1}{3.742*2\pi } \sqrt{\frac{k}{m} }$ x $2\pi \sqrt{\frac{m}{k} }$

==> 1/3.742 = <em>0.27</em>

7 0

3 years ago

I will give more points <br>for this thank you I u helped<br>me

scZoUnD [109]

Answer:

weight = mass×gravity

15×9.8
147N

<h2>stay safe healthy and happy.</h2>

6 0

3 years ago

A piano string having a mass per unit length equal to 5.20 10-3 kg/m is under a tension of 1 450 N. Find the speed with which a

DedPeter [7]

Answer:

The wave in the string travels with a speed of 528.1 m/s

Explanation:

Wave speed of sound waves in a string, v, is related to the Tension in the string, T, and the mass per unit length, μ, by the relation,

v = √(T/μ)

μ = 5.20 × 10⁻³ kg/m

T = 1450N

v = √(1450/0.0052) = 528.1 m/s

Hope this Helps!!!

6 0

3 years ago

Is the study of muscle movement in the human body and example of biology and physics

Thepotemich [5.8K]

Yes, in broader terms for people who actually study this, this is called biomechanics. Bio refers to the human body and it moving, while the physics part comes in when a ball is thrown for example and you want to know how far it is thrown.

3 0

4 years ago