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Dima020 [189]
3 years ago
14

Which of the following statements is true about the potential energy found in fossil fuels?

Physics
1 answer:
Varvara68 [4.7K]3 years ago
6 0
I'm pretty Sure it's A. Burning fossil fuels releases energy and causes air pollution.    But I could be wrong.

You might be interested in
C) An identical spring is pulled with a force or 75 N The elastie limit of the spring is 72N
tiny-mole [99]

Answer:

Spring cannot return to its original, since a part of its deformation is <u>plastic</u>, not <u>elastic</u>.

Explanation:

Physically speaking, stress is equal to the axial force divided by effective transversal area of spring. In addition, springs have usually a linear relationship between stress and strain in <u>elastic region</u>, since they are made of ductile materials. Axial force is directly proportional to axial stress, which is also directly proportional to axial strain.

Then, if force is greater than force associated with elastic limit of the spring, then spring cannot return to its original, since a part of its deformation is <u>plastic</u>, not <u>elastic</u>.

8 0
3 years ago
Given that:<br><br> = 2i + 9j ; and ⃗ = -i – 4j . Find . ⃗ ​
Marat540 [252]

Answer:

A.B = -38

Explanation:

A = 2i + 9j and B = -i - 4j.

So, A.B = (2i + 9j).(-i - 4j)

= 2i.(-i) + 2i.(-4j) + 9j.(-i) + 9j.(-4j)

= -2i.i - 8i.j - 9j.i - 36j.j

since i.i = 1, j.j = 1, i.j = 0 and j.i = 0, we have

A.B = -2(1) - 8(0) - 9(0) - 36(1)

A.B = -2 - 0 - 0 - 36

A.B = -38

5 0
3 years ago
Two blocks A and B with mA = 2.2 kg and mB = 0.84 kg are connected by a string of negligible mass. They rest on a frictionless h
madreJ [45]

Answer:

(a) a = 1.875 m/s²

(b)T = 1.575 N

(c)T increase

Explanation:

Newton's second law:

∑F = m*a Formula (1)

∑F : algebraic sum of the forces in Newton (N)

m : mass s (kg)

a : acceleration  (m/s²)

We define the x-axis in the direction parallel to the movement of the blocks on the horizontal surface and the y-axis in the direction perpendicular to it.

Forces acting on the block  A

WA: Weight of of the A block : In vertical direction  downaward (-y)

NA : Normal force of the A block :In vertical direction  upaward (+y)

F= 5.7 N  In in the direction parallel to the movement of the blocks (+x)

T :  tension of the string: In in the direction (-x)

Forces acting on the block  B

WB: Weight of the B block: In vertical direction  downaward (-y)

NB : Normal force of the B block :In vertical direction  upaward (+y)

T :  tension of the string: In in the direction (+x)

Data

mA = 2.2 kg

mB = 0.84 kg

(a) Magnitude of the acceleration  of the blocks

Newton's second law to B block:

∑Fx = m*a

T = (0.84)*a Equation (1)

Newton's second law to A block:

∑Fx = m*a

5.7 - T = (2.2)*a  We replace T of the Equation (1)

5.7 - (0.84)*a = (2.2)*a  

5.7 = (2.2)*a + (0.84)*a  Equation (2)

5.7 =(3.04)*a

a =5.7 / (3.04)

a = 1.875 m/s²

(b)Tension (in N) in the string connecting the two blocks

We replace data in the  Equation (1)

T = (0.84)*a

T = (0.84)*(1.875)

T = 1.575 N

(c) How will the tension in the string be affected if mA is decreased?

We observed Equation (2)

5.7 = (2.2)*a + (0.84)*a

5.7 = (mA)*a + (0.84)*a

5.7 =a*( mA+ 0.84)

if mA decrease , then, the acceleration increase and T  increase

4 0
3 years ago
A student is running at her top speed of 5. 4m/s to catch a bus.
Kay [80]

Answer:

A student is running at her top speed of 5. 4m/s to catch a bus.

Explanation:

Thats to fast

8 0
2 years ago
(a) Determine the specific volume of nitrogen gas at 8.5 MPa and 139 K based on the generalized compressibility chart (Fig. A-15
Vikentia [17]

Answer:v=0.0485m^3/kg

Explanation:

PV=MRT

PV/M=RT

Pv=RT

P=8.5mpa= 850Kpa

T= 139K

v= RT/P

0.2968*139/850

v=0.0485m3/kg

Error

0.0485-0.002002/0.0485*100%

95%

4 0
3 years ago
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