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Dima020 [189]
2 years ago
14

Which of the following statements is true about the potential energy found in fossil fuels?

Physics
1 answer:
Varvara68 [4.7K]2 years ago
6 0
I'm pretty Sure it's A. Burning fossil fuels releases energy and causes air pollution.    But I could be wrong.

You might be interested in
Can a average velocity be zero.Why? ​
marishachu [46]

<u>Answer:</u>

Yes

<u>Explanation:</u>

Average velocity is the ratio of total displacement and time taken for that displacement:

average \space\ velocity = \frac{displacement}{time}

This means if displacement is zero, then average velocity will also be zero.

Displacement is zero when an object moves some distance in one direction, and then moves the same distance but in the opposite direction.

∴ As it is possible for displacement to be zero, it is also possible for average velocity to be zero.

4 0
2 years ago
Find the ratio of effusion rates of hydrogen gas and krypton gas.
algol13

Answer:

RE of Hydrogen = 6.47 x RE of Krypton

Explanation:

Actually the correct formula for comparing rate of effusion (RE) of two gases is:

RE of Gas A

------------------- = √ ( Molar mass of B / Molar mass of A)

RE of Gas B

You can designate which of the two gases you have (hydrogen and krypton) will be your gas A and gas B. So for this particular problem, let us make hydrogen as gas A and Krypton as gas B. So the equation becomes:

RE of Hydrogen

------------------------- = √ (Molar mass of Krypton / Molar mass of Hydrogen)

RE of Krypton

Get the molar masses of Hydrogen and Krypton in the periodi table:

RE of Hydrogen

------------------------- = √ (83.798 g/mol / 2 g/mol)

RE of Krypton

RE of Hydrogen

------------------------- = 6.47  ====> this can also be written as:

RE of Krypton

RE of Hydrogen = 6.47 x RE of Krypton

It means that the rate of effusion of Hydrogen gas will be 6.47 faster than the rate of effusion of Krypton gas. With the type of question you have, it doesn't matter which gases goes on your numerator and denominator. What's important is that you show the rate of effusion of a gas with respect to the other. But if that's concerns you the most, then take the gas which was stated first as your gas A and the latter as your gas B unless the problem tells you which one will be on top and which is in the bottom.

3 0
3 years ago
Is the facceleration due to gravity the same on Earth and Earth's moon?
Alchen [17]

Answer:

Earth's average surface gravity is about 9.8 meters per second per second. ... The Moon's surface gravity is weaker because it is far less massive than Earth. A body's surface gravity is proportional to its mass but inversely proportional to the square of its radius.

Explanation:

3 0
3 years ago
Quadrupling the power output from a speaker emitting a single frequency will result in what increase in loudness (in units of dB
Leviafan [203]

Answer:

<em>6.02 dB increase  </em>

<em></em>

Explanation:

Let us take the initial power from the speaker P' = P Watt

then, the final power P = 4P Watt

for a given unit area, initial intensity (power per unit area) will be

I' = P Watt/m^2

and the final quadrupled sound will produce a sound intensity of

I = 4P Watt/m^2

Increase in loudness is gotten from the relation

ΔL =  10log_{10} \frac{I}{I'}

where

I = final sound intensity

I' = initial sound intensity

imputing values of the intensity into the equation, we have

==>  10log_{10} \frac{4P}{P} =  10log_{10} 4 = <em>6.02 dB increase  </em>

6 0
2 years ago
rectangular plate, whose streamwise dimension (or chord c) is 0.2 m and whose width (or span b) is 1.8 m, is mounted in a wind t
Andrei [34K]

Answer:

See explaination for the details of the answer.

Explanation:

Density is a measurement that compares the amount of matter an object has to its volume. An object with much matter in a certain volume has high density An object with little matter in the same amount of volume has a low density. Density is found by dividing the mass of an object by its volume.

The Calculate of the chordwise distribution of the skin friction coefficient and the displacement thickness is done and represented in the attachment.

Please kindly check attachment for the step by step answer.

8 0
3 years ago
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