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N76 [4]
3 years ago
9

You find it takes 220 n of horizontal force to move an unloaded pickup truck along a level road at a speed of 2.4 m/s. you then

load up the pickup and pump up its tires so that its total weight increases by 42% while the coefficient of rolling friction decreases by 19%.
Physics
1 answer:
Vinvika [58]3 years ago
3 0
Kinetic friction for the truck is given by:

F = μ*N = μ*m*g

μ coefficient of friction
m mass of the truck
g gravitational constant = 9.81

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A constant force of 120 N pushes a 55 kg wagon across an 8 m level surface. If the wagon was initially at rest, what is the fina
Illusion [34]

Answer:

The kinetic energy of the wagon is 967.0 J

Explanation:

Given that,

Force = 120 N

Mass = 55 kg

Height = 8 m

We need to calculate the kinetic energy of the wagon

Using newtons law

F = ma

\dfrac{120}{55}=a

a =2.2\ m/s^2

Using equation of motion

v^2 =u^2+2as

Where,

v = final velocity

u = initial velocity

s = height

Put the value in the equation

v^2=0+2\times2.2\times8

v=5.93\ m/s

Now, The kinetic energy is

K.E=\dfrac{1}{2}mv^2

K.E=\dfrac{1}{2}\times55\times(5.93)^2

K.E=967.0\ J

Hence, The kinetic energy of the wagon is 967.0 J

3 0
3 years ago
is plugged into the outlet of a 120−V circuit that has a 20−A circuit breaker. You plug an electric hair dryer into the same out
WINSTONCH [101]

Answer:

Given the point of maximun electric power of the hair dryer 1500 (w); The circuit breaker won´t trip at all

Explanation:

The most simplyfied  relation between power, voltage and current is:

Electric power (in watts) =Voltage (in volts) * current (in ampers)

In the case of P= 1500 (w) and V= 120 (v) we have:

I = 1500/120 (a)    = 12,65 (a)

This value  is far away of 20 (a) (the nominal trip current

8 0
3 years ago
Suppose that the coefficient of kinetic friction between Zak's feet and the floor, while wearing socks, is 0.250. Knowing this,
insens350 [35]

Answer:

The distance travel before stopping is 1.84 m

Explanation:

Given :

coefficient of kinetic friction \mu_{k} = 0.250

Zak's speed v = 3 \frac{m}{s}

Gravitational acceleration g = 9.8 \frac{m}{s^{2} }

Work done by frictional force is given by,

  W = \Delta K

 \mu _{k} mg d = \frac{1}{2} m v^{2}

  d = \frac{v^{2}  }{2 g \mu _{k} }

  d = \frac{9}{2 \times 9.8 \times 0.250}

  d = 1.84 m

Therefore, the distance travel before stopping is 1.84 m

3 0
3 years ago
What do all waves, including sound and light, have in common​
Schach [20]

Answer:

They all have frequency, wavelength, amplitude, speed and also all transfer energy.

6 0
3 years ago
75 kilometers per hour is an example of:<br> A. speed.<br> B. velocity<br> C. acceleration
kherson [118]
The answer is A. speed
hope this helps! :D

5 0
3 years ago
Read 2 more answers
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