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3 years ago

The two products that are formed when a solution of HNO3 and a solution of NaOH react are water and?

Chemistry

2 answers:

Naily [24]3 years ago

4 0

Answer:

NaNO3

Explanation:

Hello,

In this case, the required reaction is an acid-base neutralization reaction which is said to be:

$HNO_3+NaOH\rightarrow NaNO_3+H_2O$

There, we see that the sodium displaced the hydrogen in the nitric acid to form sodium nitrate a very used salt in the industry, so, as a result of that displacement, water is formed as the secondary neutralization product. For the above mentioned, answer is NaNO3 .

Best regards.

Annette [7]3 years ago

3 0

Answer: NaNO3

Explanation:

A salt sodium nitrate (NaNO3) is formed alongside water (H2O) when HNO3 and a solution of NaOH undergoes a neutralization reaction.

HNO3 + NaOH --------> NaNO3 + H2O

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What are equation for the chemical change that produces water from two hydrogen molecules and one oxygen molecule. And the react

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Answer:

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products: H2O

Explanation:

The simple reaction that produces a water molecule from H2 and O would be the one written above, even though there are 2 hydrogen molecules, they will form an H2 molecule rather than 2 individual H molecules (almost never seen) the reactants would be your hydrogen and oxygen molecules individually before they bond to form a molecule of water (H2O) which is the product

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3 years ago

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jolli1 [7]

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4 years ago

Pure carbon dioxide (PCO2 = 1 atm) decomposes at high temperature. For the reaction system 2 〖CO〗_2 (g) ⇌2 CO(g)+ O_2 (g) Is thi

julia-pushkina [17]

Answer:

The reaction decomposes more as T increases, therefore it is ENDOTHERMIC, meaning it requires energy to form CO and O₂.

Kp for each specie...

Kp = CO^2 O2 / (CO2)^2

for

T = 1500

Assume 1 atm for CO2, after % dissociation

P-CO2 left = 1*(1-0.048/100)= 0.99952

P-CO formed = 1-0.99952 = 0.00048

P-O2 = (1-0.99952)/2 = 0.00024

so..

Kp = CO^2 O2 / (CO2)^2

Kp = (0.00048^2)(0.00024) / (0.99952^2) = 5.53*10^-11

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Assume 1 atm for CO2, after % dissociation

P-CO2 left = 1*(1-17.6/100)= 0.824

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so..

Kp = CO^2 O2 / (CO2)^2

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Assume 1 atm for CO2, after % dissociation

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so..

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Explanation:

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3 years ago