Answer:
Mass = 114.5 g
Explanation:
Given data:
Mass of zinc = 55 g
Mass of ZnCl₂ produced = ?
Solution:
Chemical equation:
Zn + 2HCl → ZnCl₂ + H₂
Number of moles of Zn:
Number of moles = mass/molar mass
Molar mass of Zn = 65.4 g/mol
Number of moles = 55 g/ 65.4 g/mol
Number of moles = 0.84 mol
Now we will compare the moles of Zn and zinc chloride,
Zn : ZnCl₂
1 : 1
0.84 : 0.84
Mass of ZnCl₂:
Mass = number of moles × molar mass
Molar mass of ZnCl₂= 136.3 g/mol
Mass = 0.84 mol × 136.3 g/mol
Mass = 114.5 g
I believe your answer is Favorable.
Hope this helps, and happy studying~!
~{Dunsforhands}
Answer:
if i remember correctly i beleive its A 1.8 x 10^24
but im not for sure also i think you forgot the 24
Explanation:
Answer:
6.78 × 10⁵ J
Explanation:
Step 1: Given and required data
- Latent heat of vaporization of water (ΔH°vap): 2260 J/g
Step 2: Calculate the heat (Q) required to vaporize 300 grams of water
We will use the following expression.
Q = ΔH°vap × m
Q = 2260 J/g × 300 g
Q = 6.78 × 10⁵ J
6.78 × 10⁵ Joule will be required to convert 300 g of water to steam at 100 °C.