Question

Two 0.75 Amp loads are connected in parallel with a 2500 Milliamperehour Ni-Cd battery. Approximately how long can the battery provide power to the load?

Answer 1

Explanation:

It is given that two loads have 0.75 Ampere current each. And, they contain 2500 milli ampere per hour Ni-Cd battery.

As both the loads are connected in parallel. Hence, total current will be calculated as follows.

               I = $I_{1} + I_{2}$

                 = 0.75 A + 0.75 A

                 = 1.5 A

                 = $1.5 A \times \frac{1000 mA}{1 A}$

                 = 1500 mA

Relation between time and capacity of battery is as follows.

             Capacity = Current × time (in hour)

therefore,        time = $\frac{Capacity}{Current}$

                                = $\frac{2500 mA. h}{1500 A}$

                                = 1.667 hr

Thus, we can conclude that the battery provide power to the load up to 1.667 hours.