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Mashcka [7]
3 years ago
9

PRACTICE

Mathematics
1 answer:
Novay_Z [31]3 years ago
4 0

Answer:

k = 20

Step-by-step explanation:

Expressing 18, 36 and 54 as a product of their prime factors

18 = 2 × 3 × 3 = 2 × 3²

36 = 2 × 2 × 3 × 3 = 2² × 3²

54 = 2 × 3 × 3 × 3 = 2 × 3³

The common prime factors are 2 and 3²

HCF = 2 × 3² = 2 × 9 = 18

Thus

k - 2 = 18 ( add 2 to both sides )

k = 20

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The first one is right the rest of them is not right correct

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Caroline's gross annual salary is $47,448 What is the max amount of rent she can afford to pay?
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47,448/12=$3954

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The variable Z is directly proportional to X. When X is 6, Z has the value 18.
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Read 2 more answers
The amount of money spent weekly on cleaning, maintenance, and repairs at a large restaurant was observed over a long period of
Ipatiy [6.2K]

Answer:

a) 0.4121

b) $588

Step-by-step explanation:

Mean μ = $633

Standard deviation σ = $45.

Required:

a. If $646 is budgeted for next week, what is the probability that the actual costs will exceed the budgeted amount?

We solve using z score formula

= z = (x-μ)/σ, where

x is the raw score

μ is the population mean

σ is the population standard deviation.

For x = $646

z = 646 - 633/45

z = 0.22222

Probability value from Z-Table:

P(x<646) = 0.58793

P(x>646) = 1 - P(x<646) = 0.41207

≈ 0.4121

b. How much should be budgeted for weekly repairs, cleaning, and maintenance so that the probability that the budgeted amount will be exceeded in a given week is only 0.16? (Round your answer to the nearest dollar.)

Converting 0.16 to percentage = 0.16 × 100% = 16%

The z score of 16%

= -0.994

We are to find x

Using z score formula

z = (x-μ)/σ

-0.994 = x - 633/45

Cross Multiply

-0.994 × 45 = x - 633

-44.73 = x - 633

x = -44.73 + 633

x = $588.27

Approximately to the nearest dollar, the amount should be budgeted for weekly repairs, cleaning, and maintenance so that the probability that the budgeted amount will be exceeded in a given week is only 0.16

is $588

7 0
3 years ago
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