The values of the functions are f(4) = 47, f(k) = 2(k)^2 + 4(k) - 1 and f(x + h) = 2x^2 + 4hx + 2h^2 + 4x + 4h - 4
<h3>How to evaluate the expression?</h3>
The function is given as:
f(x) = 2x^2 + 4x - 1
To calculate f(4), we have:
f(4) = 2(4)^2 + 4(4) - 1
Evaluate the expression
f(4) = 47
To calculate f(k), we have:
f(k) = 2(k)^2 + 4(k) - 1
To calculate f(x + h), we have:
f(x + h) = 2(x + h)^2 + 4(x + h) - 1
Expand
f(x + h) = 2(x^2 + 2hx + h^2) + 4x + 4h - 4
Expand
f(x + h) = 2x^2 + 4hx + 2h^2 + 4x + 4h - 4
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Answer:
Step-by-step explanation:
By the Triangle Proportionality Theorem:
By cross-multiplication:
Distribute:
Subtract 12x from both sides:
Hence:
Answer:
y = - x + 2
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c
Rearrange 2x + 3y = 6 into this form
Subtract 2x from both sides
3y = - 2x + 6 ( divide all 3 terms by 3 )
y = - x + 2 ← in slope- intercept form
D is 11
2d - 5 = 17 add 5 to both sides
2d = 22 divide by 2
d = 11 answer