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lapo4ka [179]
3 years ago
8

What compound was formed by the reaction of the first oxygen released by cyanobacteria and iron?

Chemistry
1 answer:
castortr0y [4]3 years ago
7 0
The compound that was formed by the reaction of the first oxygen released by Cyanobacteria and iron are the metals of the earths crust. Cyanobacteria was the first organisms that used water instead of hydrogen sulfide or other compounds as a source of electrons and hydrogen for fixing carbon dioxide. Early Cyanobacteria inhabited marine sediments where Archean banded iron formations were deposited; consisting of reddish layers rich in iron oxide. 
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Which statement best explains how organ systems work together to remove wastes?
soldier1979 [14.2K]

Answer:

B

Explanation:

Carbon Dioxide is one of waste produced from Our cells during respiration. The circulatory system carries Carbon Dioxide from cells either in haemaglobin in RBC or plasm. The Carbon Dioxide being carried to blood cappilaries near alveoli before diffused into alveoli and then being removed away by respiratory system in the process of respiration while we exhale

5 0
3 years ago
Determine the net iconic equation for the following chemical reaction: HCl(aq) + NH4OH(aq)———-> NH4Cl(aq) + H2O(I) Hint: HCl(
katen-ka-za [31]

Answer : The net ionic equation will be,

H^{+}(aq)+OH^{-}(aq)\rightarrow H_2O(l)

Explanation :

In the net ionic equations, we are not include the spectator ions in the equations.

Spectator ions : The ions present on reactant and product side which do not participate in a reactions. The same ions present on both the sides.

The given balanced ionic equation will be,

HCl(aq)+NH_4OH(aq)\rightarrow NH_4Cl(aq)+H_2O(l)

The ionic equation in separated aqueous solution will be,

H^+(aq)+Cl^-(aq)+NH_4^+(aq)+OH^-(aq)\rightarrow H_2O(l)+NH_4^+(aq)+Cl^-(aq)

In this equation, NH_4^+\text{ and }Cl^- are the spectator ions.

By removing the spectator ions from the balanced ionic equation, we get the net ionic equation.

The net ionic equation will be,

H^{+}(aq)+OH^{-}(aq)\rightarrow H_2O(l)

5 0
3 years ago
What is the relationship between mass and solubility
disa [49]

Answer:

Higher molar mass compounds will be less soluble than lower molar mass molecules of the same type.

Explanation:

Bigger Mass = slower/less soluble

Small Mass = faster/more soluble

8 0
3 years ago
Read 2 more answers
If each of the following compounds/ions were placed between 2 electrically charged plates (one positive and one negative) Which
GREYUIT [131]
<span>If a molecule wants to interact with an electric field. it should have a permanent dipole momentum. so first check the polarity. for example CH4 is not polar. CH2Cl2 is polar (so yes), H3O)+ is obvious that is polar. H2O yes. C2H2Cl2 in trans form is not polar but in cis form yes. CO2 is non-polar. Ozone is polar. </span>
4 0
2 years ago
What is the pH of 0.26 M ammonium ion? NH4+(aq) + H2O(1) NH3(aq) + H30* (aq) a. 4.33 b.9.25 c. 3.87 d. 4.92 e. 4.75
choli [55]

Answer:

b) pH = 9.25

Explanation:

  • NH4+(aq)  +  H2O(l)  ↔  NH3(aq)  +  H3O+(aq)
  • NH3 + H2O ↔ NH4+  +  OH-
  • 2 H2O ↔ H3O+  +  OH-

⇒ Kb = [ NH4+ ] * [ OH- ] / [ NH3 ] = 1.86 E-5......from literature

mass balance NH4+:

⇒ M NH4+ = [ NH4+ ] - [ OH- ]

∴ [ NH3 ] ≅ M NH4+ = 0.26 M

⇒ Kb = (( 0.26 + [ OH- ] )) * [ OH- ] / 0.26 = 1.86 E-5

⇒ 0.26 [ OH-] + [ OH- ]² = 4.836 E-6

⇒ [ OH- ]² + 0.26 [ OH- ] - 4.836 E-6 = 0

⇒ [ OH- ] = 1.859 E-5 M

⇒ pOH = - Log ( 1.859 E-5 )

⇒ pOH = 4.7305

⇒ pH = 14 - pOH = 9.269

6 0
3 years ago
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