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LenKa [72]
3 years ago
7

What are examples of a medium?

Physics
1 answer:
alekssr [168]3 years ago
4 0
I think it’s b amplitude and wavelength
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Describe Charle’s Law and Boyle’s Law.
ch4aika [34]

Explanation:

Boyle's law can be stated as the "volume of a fixed mass of a gas varies inversely as the pressure changes if the temperature is constant". It is mathematically expressed as;

    P1 V1  = P2 V2

P1 is the initial pressure

V1 is the initial volume

P2 is the final pressure

V2 is the final volume

Charles's law states that the volume of a fixed mass of a gas varies directly as its absolute temperature if the pressure is constant.

It is mathematically expressed as;

            \frac{V1}{T1}    = \frac{V2}{T2}  

V and T are volume and temperature respectively

1 and 2 are the initial and final states

8 0
3 years ago
Please help me i dont understand it <br><br><br><br> This subject is Earth science
Anton [14]
Here are your answers

6 0
3 years ago
Can a bullet and an automobile have the same momentum? Fully explain your answer.
noname [10]
Yes, but the velocity of the bullet would have to be much higher. Because momentum is defined as p=mv, for a bullet, which has a much, much smaller mass than a car or a truck, to have the same value for p, v_b_u_l_l_e_t\ \textgreater \ \ \textgreater \ v_a_u_t_o_m_o_b_i_l_e
5 0
4 years ago
A 2.0 m conductor is formed into a square and placed in the horizontal A magnetic field is oriented above the horizontal with a
pashok25 [27]

Answer:

<h3>4.0Wb/m²</h3>

Explanation:

Magnetic flux Ф is expressed using the formula;

Ф = BA

B is magnetic field

A is the area of the square conductor

Given

B = 1.0T

A =L²

Area A = 2.0² = 4.0m²

Get the magnetic flux

Ф = 1.0 * 4.0m²

Ф = 4.0Wb/m²

Hence the magnetic flux through the conductor is 4.0Wb/m²

8 0
3 years ago
A box is moved 20 m across a smooth floor by a force making a downward angle with the floor, so that there is effectively a 10 N
Usimov [2.4K]

Answer:

100 J

Explanation:

From the question, The work done by the forces in moving the box is given as

W = FxdcosФ+Fydcosα................... Equation 1

Where W = Work done, Fx = force acting parallel to the floor, d = distance moved by the box, Ф = angle the parallel force makes with the floor, Fy = force acting perpendicular to the floor, α = angle the perpendicular force make with the floor.

Give: Fx = 10 N, d = 20 m, Fy = 5 N, Ф = 0°, α = 90°

Substitute into equation 1

W = 10×10×cos0°+5×20×cos90°

W = 10×10×1+0

W = 100 J.

Note: The work done by the perpendicular force is zero

Hence the work done = 100 J

5 0
3 years ago
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