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Julli [10]
3 years ago
10

Write the equation

Mathematics
1 answer:
andrew11 [14]3 years ago
8 0

Two things must be performed to make an equation that satisfies this. First, we need to come up with a general equation that is perpendicular to the one in the problem. To do this, the reciprocal of the slope is calculated (negative inverse). The line that is perpendicular to y=1/8x + 2 has a slope of -8. This is what our equation looks like so far:

y’=-8x

This is good, but it doesn’t pass through (1,5). To make it do this, put the point in the equation and solve it - a point on a graph that intersects the line is a “solution” of the equation, so we need to solve for it!

y’ = -8x

(5) = -8(1)

Nope, 5 doesn’t equal -8. Let’s make the two sides equal by adding 13 to the right side.

y’ = -8x + 13

(5) = -8(1) + 13

5=5 - yes!

Our equation that is perpendicular to the one in the question and also passes through the point (1, 5) is y’=-8x + 13.

Hope this helps!

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Which describes an isometric transformation? dilation/ rotation/ side length change/ angle change
Westkost [7]

Answer:

  rotation

Step-by-step explanation:

"Isometric" means all measures stay the same.

  • dilation changes all lengths
  • <em>rotation changes no measures -- an isometric transformation</em>
  • side length change obviously changes the length of a side
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7 0
3 years ago
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dalvyx [7]

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Step-by-step explanation:

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Sedbober [7]
1st one 17/100 2nd one 0.25


Because 0.17 would be like 17% out of 100% so the fraction simplified is 17/100

2. Since the area of a square is length×length
But according to the question we are asked to find the length and the area is given so we will have to solve this
L×L= area
L^2=0.25
Square root both sides
L=√0.25
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6 0
3 years ago
What is the slope of this line?
kumpel [21]

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Step-by-step explanation:

4 0
3 years ago
I need an accurate answer please
kotykmax [81]

x = –6

Solution:

Given expression is \sqrt[3]{x-2}+5=3.

Step 1: Isolate the radical by subtracting 5 from both sides of the equation.

\Rightarrow\sqrt[3]{x-2}+5-5=3-5

\Rightarrow\sqrt[3]{x-2}=-2

Step 2: Cube both sides of the equation to remove the cube root.

\Rightarrow(\sqrt[3]{x-2})^3=(-2)^3

Cube and cube root get canceled in left side of the equation.

\Rightarrow\ x-2=-8

Step 3: To solve for x.

Add 2 on both sides of the equation.

\Rightarrow\ x-2+2=-8+2

\Rightarrow\ x=-6

Hence the solution is x = –6.

6 0
2 years ago
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