Answer ASAP Pls don't use links

A kicked soccer ball eventually comes to rest. What force causes this? ce

maks197457 [2]

Answer:

friction

Explanation:

jwjwkkskskaksksk

7 0

2 years ago

Guys help me out please

kifflom [539]

Answer:

See explanation

Explanation:

A net ionic equation shows only the chemical species that are involved in a reaction, while a complete ionic equation also includes the spectator ions(Khan Academy).

From the species shown in the image we can write the molecular equation, ionic equation and net ionic equation and also identify the spectator ions.

Chemical equation: KX + BY --------> BX + AY

Ionic Equation; X^- + A^+ + B^+ + Y^- -----> BX + A^+ + Y^-

Spectator ions; A^+ and Y^-

Net Ionic Equation; X^- + B^+ ------> BX

7 0

2 years ago

What are is a most important event in causing geysers

Montano1993 [528]

Heat underneath the ground making its water boil

8 0

3 years ago

A polyatomic ion contains 18 protons and 20 electrons. the net charge if this ion is ___?

andrew11 [14]

-2 cuz 20 negative minus 18 positive is -2

6 0

2 years ago

Read 2 more answers

In the laboratory a student combines 26.2 mL of a 0.234 M chromium(III) acetate solution with 10.7 mL of a 0.461 M chromium(III)

Natalka [10]

Answer: The molarity of $Cr^{3+}$ ions in the solution is 0.299 M

Explanation:

To calculate the number of moles for given molarity, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}\times 1000}{\text{Volume of solution (in mL)}}$ .....(1)

For chromium (III) acetate:

Molarity of chromium (III) acetate solution = 0.234 M

Volume of solution = 26.2 mL

Putting values in equation 1, we get:

$0.234=\frac{\text{Moles of chromium (III) acetate}\times 1000}{26.2}\\\\\text{Moles of chromium (III) acetate}=\frac{0.234\times 26.2}{1000}=0.00613mol$

1 mole of chromium (III) acetate $(Cr(CH_3COO)_3)$ produces 1 mole of chromium $(Cr^{3+})$ ions and 3 moles of acetate $(CH_3COO^-)$ ions

Moles of $Cr^{3+}\text{ ions}=(1\times 0.00613)=0.00613moles$

For chromium (III) nitrate:

Molarity of chromium (III) nitrate solution = 0.461 M

Volume of solution = 10.7 mL

Putting values in equation 1, we get:

$0.461=\frac{\text{Moles of chromium (III) nitrate}\times 1000}{10.7}\\\\\text{Moles of chromium (III) nitrate}=\frac{0.461\times 10.7}{1000}=0.00493mol$

1 mole of chromium (III) nitrate $(Cr(NO_3)_3)$ produces 1 mole of chromium $(Cr^{3+})$ ions and 3 moles of nitrate $(NO_3^-)$ ions

Moles of $Cr^{3+}\text{ ions}=(1\times 0.00493)=0.00493moles$

For chromium cation:

Total moles of chromium cations = [0.00613 + 0.00493] = 0.01106 moles

Total volume of solution = [26.2 + 10.7] = 36.9 mL

Putting values in equation 1, we get:

$\text{Molarity of }Cr^{3+}\text{ cations}=\frac{0.01106\times 1000}{36.9}\\\\\text{Molarity of }Cr^{3+}\text{ cations}=0.299M/tex]Hence, the molarity of [tex]Cr^{3+}$ ions in the solution is 0.299 M

5 0

3 years ago