The bag contains,
Red (R) marbles is 9, Green (G) marbles is 7 and Blue (B) marbles is 4,
Total marbles (possible outcome) is,
Let P(R) represent the probablity of picking a red marble,
P(G) represent the probability of picking a green marble and,
P(B) represent the probability of picking a blue marble.
Probability , P, is,
Probablity of drawing a Red marble (R) and then a blue marble (B) without being replaced,
That means once a marble is drawn, the total marbles (possible outcome) reduces as well,
Hence, the best option is G.
Answer:
4/9 or 44.4%
Step-by-step explanation:
Division and addition are the only operations involved.
6810 bottles produced last month (of all three kinds)
1/3 of the 6810 were orange = 2270 are the oranges so 6810-2270 = 4540 (both limes and apples)
apples = 3 * limes
apples count is N
limes count is n
N=3n
N+n=4540
3n+n=4540
4n=4540
n=1135 (limes)
N= 3n = 3405 (apples)
To eliminate x, you can multiply the second equation by 2. This will make -2x into -4x, so that 4x and 4x will be able to cancel out leaving you to solve for y.
To eliminate y, you can multiply the second equation by 3. This will make 3y into 9y, so that -9y and 9y will be able to cancel out leaving you to solve for x.
Hope this helped.
