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Scilla [17]
3 years ago
9

Let $\angle D$ be an acute angle such that $\tan D=0.72$ . Use a calculator to approximate the measure of $\angle D$ to the near

est tenth of a degree.
Mathematics
1 answer:
pentagon [3]3 years ago
4 0

Answer:

D = 35.8 degrees

Step-by-step explanation:

In this question, we are asked to use calculator to estimate the approximate measure of angle D given its tan value.

From the question, what we have is;

tan D = 0.72

Now to calculate the acute angle D, we will divide through by tan

hence,

D = tan^-1 0.72

or more simply tan^-1 can be called arc tan

Thus, D = arc tan 0.72

D = 35.75

D = 35.8 to the nearest tenth of a degree

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PLEASE HELP!! “Find the value of x and round your answer to the nearest degree. Show your work.”
KonstantinChe [14]

Answer:

Step-by-step explanation:

sinx = 17/22

x = arcsin(17/22)

x = 50.599431246...°

x = 51°

4 0
3 years ago
45. Real Estate Appreciation Bob Michaels purchased a
Tju [1.3M]

Answer:

a)

Since t is between 0 and 15, and the house was purchased 8 years ago, we have two pairs of values:

  • t = 0, V(0) = 42000
  • t = 8, V(8) = 67500

<u>Find the slope, m:</u>

  • m = (67500 - 42000)/8 = 3187.50

The value of b is 42000, since at t = 0, V = 42000

<u>So the equation is:</u>

  • V = 3187.50t + 42000

b)

The graph is attached.

When V = 72500, t = 9.6 (approximately)

c)

When V = 74000

  • 74000 = 3187.5t + 42000
  • 3187.5t = 32000
  • t = 32000/3187.5
  • t ≈ 10 years (rounded down)

d)

When V = 80250

  • 80250 = 3187.5t + 42000
  • 3187.5t = 80250 - 42000
  • 3187.5t = 38250
  • t = 38250/3187.5
  • t = 12 years

4 0
3 years ago
The price of an outdoor grill was marked up 15% over the previous year's model. If the previous year's model sold for $500, what
harkovskaia [24]
I thank the answer is 75 #I thank
8 0
3 years ago
What is the sum of the infinite geometric series?
12345 [234]

Answer:

- 288

Step-by-step explanation:

The n th term of a geometric series is

a_{n} = ar^{n-1}

- 144 (\frac{1}{2}) ^{n-1} is in this form

with a = - 144 and r = \frac{1}{2}

S_{infinity} = \frac{a}{1-r} = \frac{-144}{1-\frac{1}{2} } = \frac{-144}{\frac{1}{2} } = - 288

5 0
3 years ago
Apply the properties of integer exponents to identify all of the expressions equivalent to 1/8.
Alborosie

Answer:

The answers are A , C , D

Step-by-step explanation:

Lets revise the rule of exponent

* a^{n}*a^{m}=a^{m+n}

* \frac{a^{m}}{a^{n}}=a^{m-n}

* \frac{1}{a^{-m}}=a^{m}

* (\frac{a}{b})^{-m}=(\frac{b}{b})^{m}

Now lets solve the problem

We need all the expressions equivalent to \frac{1}{8}

A.

∵ 2^{-3}=\frac{1}{2^{3}}

∵ 2³ = 8

∴ 2^{-3}=\frac{1}{8}

Answer A is equivalent to \frac{1}{8}

B.

∵ 2³ = 8

Answer B is not equivalent to \frac{1}{8}

C.

∵ 2³ = 8

∴ \frac{1}{2^{3}}=\frac{1}{8}

Answer C is equivalent to \frac{1}{8}

D.

∵ 2^{2}*2^{-5}=2^{2+-5}=2^{-3}

∵ 2^{-3}=\frac{1}{2^{3}}=\frac{1}{8}

Answer D is equivalent to \frac{1}{8}

E.

∵ 2^{-2}*2^{5}=2^{-2+5}=2^{3}

∵ 2³ = 8

Answer E is not equivalent to \frac{1}{8}

<em>The answers are A , C , D</em>

4 0
4 years ago
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