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4 years ago

Brainliest + 30 points

Mathematics

2 answers:

Evgesh-ka [11]4 years ago

5 0

Answer:

Step-by-step explanation:

Plug the numbers into the distance formula:

$d = \sqrt{(x2 - x1)^2 + (y2-y1)^2} \\$

$d = \sqrt{(11 - 5)^2 + (16-8)^2} \\$

Then solve:

You get 10

Luden [163]4 years ago

4 0

From Geocity to Shapetown is

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How do you write 9.01 x 103 in standard form?

katen-ka-za [31]

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$9.01 \times {10}^{3} = 9.01 \times 1000 = 9010$

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8 0

3 years ago

HELP!

Anastasy [175]

The areas of the parallelograms can be compared as: A. The area of parallelogram 1 is 4 square units greater than the area of parallelogram 2.

<h3>What is a parallelogram?</h3>

A parallelogram refers to a geometrical shape and it can be defined as a type of quadrilateral and two-dimensional geometrical figure that has two (2) equal and parallel opposite sides.

<h3>How to calculate the area of a triangle?</h3>

Mathematically, the area of a triangle can be calculated by using this formula:

Area = ½ × b × h

Where:

b represents the base area.

h represents the height.

<h3>How to calculate the area of a rectangle?</h3>

Mathematically, the area of a rectangle can be calculated by using this formula;

A = LW

Where:

A represents the area of a rectangle.

l represents the length of a rectangle.

w represents the width of a rectangle.

Next, we would determine the area of the two parallelograms as follows:

Area of parallelogram 1 = Area of red-rectangular figure - Area of triangle A - Area of triangle B - Area of triangle C - Area of triangle D.

Substituting the given parameters into the formula, we have;

Area of parallelogram 1 = (6 × 6) - (½ × 4 × 2) - (½ × 2 × 4)- (½ × 4 × 2) - (½ × 2 × 4)

Area of parallelogram 1 = 36 - 4 - 4 - 4 - 4

Area of parallelogram 1 = 36 - 16

Area of parallelogram 1 = 20 units².

For parallelogram 2, we have:

Area of parallelogram 2 = Area of blue-rectangular figure - Area of triangle P - Area of triangle Q - Area of triangle R - Area of triangle S.

Substituting the given parameters into the formula, we have;

Area of parallelogram 2 = (8 × 4) - (½ × 2 × 2) - (½ × 6 × 2)- (½ × 2 × 2) - (½ × 2 × 6)

Area of parallelogram 2 = 32 - 2 - 6 - 2 - 6

Area of parallelogram 2 = 32 - 16

Area of parallelogram 2 = 16 units².

Difference = Area of parallelogram 1 - Area of parallelogram 2

Difference = 20 - 16

Difference = 4 units².

In conclusion, we can infer and logically deduce that the area of parallelogram 1 is 4 square units greater than the area of parallelogram 2.

Read more on parallelogram here: brainly.com/question/4459854

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