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3 years ago

Brainliest + 30 points

Mathematics

2 answers:

Evgesh-ka [11]3 years ago

5 0

Answer:

Step-by-step explanation:

Plug the numbers into the distance formula:

$d = \sqrt{(x2 - x1)^2 + (y2-y1)^2} \\$

$d = \sqrt{(11 - 5)^2 + (16-8)^2} \\$

Then solve:

You get 10

Luden [163]3 years ago

4 0

From Geocity to Shapetown is

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Fill in the blanks.<br><br> (x+_)^2=x^2+14x+_

Serga [27]

Step-by-step explanation:

(ax + b)² = a²x² + 2abx + b²

In this case, a = 1, so:

14 = 2b

b = 7

(x + 7)² = x² + 14x + 49

7 0

3 years ago

HELP...here say:write five decimals that have at least 3 digits to the right of the decimal point.Write the expanded form and th

just olya [345]

27÷9=3
1+2=3
1×3=3
10-7=3
27-24=3

8 0

2 years ago

Farmer Brown is prepping his circular garden for the new spring/summer season of vegetables. The garden has to be larger than 25

d1i1m1o1n [39]

Answer:

The area is 78.5, the farmer does have enough space to plant his vegetables

Step-by-step explanation:

To find the area, you need to use the formula, A=πr², (make sure the diameter is turned into the radius by dividing by 2, in this case, it's 5 as the radius)

Plug in your numbers, A= 3.14(5)²

A= 3.14(25)

The area is 78.5

So the farmer does have enough space to plant his vegetables since 78.5 is greater than 25

7 0

3 years ago

One of the roots of the quadratic equation dx^2+cx+p=0 is twice the other, find the relationship between d, c and p

scZoUnD [109]

Answer:

$c^2 = 9dp$

Step-by-step explanation:

Given

$dx^2 + cx + p = 0$

Let the roots be $\alpha$ and $\beta$

So:

$\alpha = 2\beta$

Required

Determine the relationship between d, c and p

$dx^2 + cx + p = 0$

Divide through by d

$\frac{dx^2}{d} + \frac{cx}{d} + \frac{p}{d} = 0$

$x^2 + \frac{c}{d}x + \frac{p}{d} = 0$

A quadratic equation has the form:

$x^2 - (\alpha + \beta)x + \alpha \beta = 0$

So:

$x^2 - (2\beta+ \beta)x + \beta*\beta = 0$

$x^2 - (3\beta)x + \beta^2 = 0$

So, we have:

$\frac{c}{d} = -3\beta$ -- (1)

and

$\frac{p}{d} = \beta^2$ -- (2)

Make $\beta$ the subject in (1)

$\frac{c}{d} = -3\beta$

$\beta = -\frac{c}{3d}$

Substitute $\beta = -\frac{c}{3d}$ in (2)

$\frac{p}{d} = (-\frac{c}{3d})^2$

$\frac{p}{d} = \frac{c^2}{9d^2}$

Multiply both sides by d

$d * \frac{p}{d} = \frac{c^2}{9d^2}*d$

$p = \frac{c^2}{9d}$

Cross Multiply

$9dp = c^2$

$c^2 = 9dp$

Hence, the relationship between d, c and p is: $c^2 = 9dp$

8 0

3 years ago

Choose the graphic representation of the quadratic function f(x)=x^2-8x+24

grigory [225]

The Answer is ----D----

8 0

3 years ago

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