Answer:
456
Step-by-step explanation:
Let X be the SATscore scored by the students
Given that X is normal (1000,200)
By converting into standard normal variate we can say that
is N(0,1)
To find the top 10% we consider the 90th percentile for z score
Z 90th percentile = 1.28

i.e. only students who scored 456 or above only should be considered.
15 and 21. From 1 to 3 is plus 2 and from 3 to 6 is plus 3 and from 6 to 10 is plus 4 and so on
Step-by-step explanation:
450 - 396 = 54
(54/450) * 100% = 12%
Hence the decrease is 12%.
I believe it is c because if u follow through with that using trial error u will get that answer
1058+44.50 =1102.5
1102.5-1000=102.5
102.5 is your anwser