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4 years ago

5

In the number 1.1084, how does the value of the 1 in the ones place compare to the value of the 1 in the tenths place?

1 answer:

Vlada [557]4 years ago

3 0

Answer:The value of the 1 in the ones place is 10 times the value of the 1 in the tenths place.

Step-by-step explanation:

You might be interested in

Suppose 52% of the population has a college degree. If a random sample of size 563563 is selected, what is the probability that

amm1812

Answer:

The value is $P(| \^ p - p| < 0.05 ) = 0.9822$

Step-by-step explanation:

From the question we are told that

The population proportion is $p = 0.52$

The sample size is n = 563

Generally the population mean of the sampling distribution is mathematically represented as

$\mu_{x} = p = 0.52$

Generally the standard deviation of the sampling distribution is mathematically evaluated as

$\sigma = \sqrt{\frac{ p(1- p)}{n} }$

=> $\sigma = \sqrt{\frac{ 0.52 (1- 0.52 )}{563} }$

=> $\sigma = 0.02106$

Generally the probability that the proportion of persons with a college degree will differ from the population proportion by less than 5% is mathematically represented as

$P(| \^ p - p| < 0.05 ) = P( - (0.05 - 0.52 ) < \^ p < (0.05 + 0.52 ))$

Here $\^ p$ is the sample proportion of persons with a college degree.

So

$P( - (0.05 - 0.52 ) < \^ p < (0.05 + 0.52 )) = P(\frac{[[0.05 -0.52]]- 0.52}{0.02106} < \frac{[\^p - p] - p}{\sigma } < \frac{[[0.05 -0.52]] + 0.52}{0.02106} )$

Here

$\frac{[\^p - p] - p}{\sigma } = Z (The\ standardized \ value \ of\ (\^ p - p))$

=> $P( - (0.05 - 0.52 ) < \^ p < (0.05 + 0.52 )) = P[\frac{-0.47 - 0.52}{0.02106 } < Z < \frac{-0.47 + 0.52}{0.02106 }]$

=> $P( - (0.05 - 0.52 ) < \^ p < (0.05 + 0.52 )) = P[ -2.37 < Z < 2.37 ]$

=> $P( - (0.05 - 0.52 ) < \^ p < (0.05 + 0.52 )) = P(Z < 2.37 ) - P(Z < -2.37 )$

From the z-table the probability of (Z < 2.37 ) and (Z < -2.37 ) is

$P(Z < 2.37 ) = 0.9911$

and

$P(Z < - 2.37 ) = 0.0089$

So

=> $P( - (0.05 - 0.52 ) < \^ p < (0.05 + 0.52 )) =0.9911-0.0089$

=> $P( - (0.05 - 0.52 ) < \^ p < (0.05 + 0.52 )) = 0.9822$

=> $P(| \^ p - p| < 0.05 ) = 0.9822$

3 0

3 years ago

What is 314'702 in expanded form

Tema [17]

300000 + 10000 + 4000 + 700 + 2

5 0

3 years ago

1.What is the first quartile of these numbers?

Sladkaya [172]

#1 is 4 for the 1st quartile

7 0

3 years ago

Find the minimum y-value on the graph of y=f(x)<br><br> F(x) = 7x^2 + 7 - 6

Kisachek [45]

Answer:

The minimum y-value is

$y=-\frac{31}{4}$ or $y=-7.75$

Step-by-step explanation:

we have

$f(x)=7x^{2}+7x-6$

This is the equation of a vertical parabola open up

The vertex is the minimum y-value on the graph

Convert the equation into vertex form

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$f(x)+6=7x^{2}+7x$

Factor the leading coefficient

$f(x)+6=7(x^{2}+x)$

Complete the square. Remember to balance the equation by adding the same constants to each side

$f(x)+6+1.75=7(x^{2}+x+0.25)$

$f(x)+7.75=7(x^{2}+x+0.25)$

Rewrite as perfect squares

$f(x)+7.75=7(x+0.5)^{2}$

$f(x)=7(x+0.5)^{2}-7.75$ ------> equation in vertex form

The vertex is the point (-0.5,-7.75)

therefore

The minimum is the point (-0.5,-7.75)

The minimum y-value is $y=-7.75=-7\frac{3}{4}=-\frac{31}{4}$

see the attached figure to better understand the problem

6 0

3 years ago

What expression can be used to find 7(6 1/8)

9966 [12]

Answer:

42 7/8

Step-by-step explanation:

7(6 1/8)

~Turn the 7 into a fraction and the other fraction into an improper one

7/1 * 49/8

~Multiply

343/8

~Simplify

42 7/8

3 0

3 years ago