1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
SVEN [57.7K]
3 years ago
11

Se usa una bombona de He para inflar globos, de volumen 15L con una presión de 200 atm. Si los globos tienen un volumen de 1.5L

y presión de 770mmHg. ¿Cuántos globos se pueden llenar?
Physics
1 answer:
Bingel [31]3 years ago
8 0

Answer:

La cantidad de globos llenos es de aproximadamente 1.974 globos

Explanation:

Los parámetros dados son;

El gas utilizado para inflar el globo = Él

El volumen del gas He, V₁ = 15 L

La presión del gas He, P₁ = 200 atm = 20,265,000 Pa

El volumen de cada globo = 1,5 L

La presión del He dentro del globo, P₂ = 770 mmHg = 102,641 Pa

Sea 'V₂', que represente el volumen total que el gas ocupa en todos los globos, y 'x', que represente el número de globos;

Por lo tanto, tenemos;

1,5 · x = V₂

Según la ley de Boyle, tenemos;

P₁ · V₁ = P₂ · V₂

∴ V₂ = P₁ · V₁ / (P₂)

Al introducir los valores conocidos, obtenemos;

V₂ = 20,265,000 Pa × 15 L / (102,641 Pa) = 2,961.53548 L

1,5 L × x = V₂

∴ 1,5 L × x = 2,961,53548 L

x = 2,961.53548 L / (1.5 L) = 1,974.35699 redondeamos hacia abajo para obtener un número entero de globos de la siguiente manera;

El número de globos, x ≈ 1,974 globos.

You might be interested in
A coffee mixture has beans that sell for $0.72 a pound and beans that sell for $0.52. If 110 pounds of beans create a mixture wo
Burka [1]
X is a weight of the beans that sells for $0.72 apound
y is a weight of the beans that sells for $0.52 a pound
{x+y=110
{0.72x+0.52y=110*0.74

x=110-y
0.72*(110-y)+0.52y=81.4
79.2-0.72y+0.52y=81.4
-0.2y=2.2

Just use 110 pounds of beans that cost $0.52 and your revenue will be 
30 percents
Or use 110 pounds of beans that cost $0.72 and your revenue will be
2.7 percents
7 0
4 years ago
A soccer goal is 2.44 m high. A player kicks the ball at a distance 13 m from the goal at an angle of 40°, and the ball just hit
Vera_Pavlovna [14]

Let <em>v</em> denote the initial speed of the ball. The ball's position at time <em>t</em> is given by the vector

\mathbf r(t)=v\cos40^\circ\,t\,\mathbf i+\left(v\sin40^\circ\,t-\dfrac g2t^2\right)\,\mathbf j

where <em>g</em> is the acceleration due to gravity with magnitude 9.80 m/s^2.

The ball reaches the goal 13 m away at time <em>t</em> such that

10\,\mathrm m=v\cos40^\circ t\implies t=\dfrac{10\,\mathrm m}{v\cos40^\circ}

at which point it attains a height of 2.44 m, so that

2.44\,\mathrm m=v\sin40^\circ\left(\dfrac{10\,\mathrm m}{v\cos40^\circ}\right)-\dfrac g2\left(\dfrac{10\,\mathrm m}{v\cos40^\circ}\right)^2

2.44\,\mathrm m=(10\,\mathrm m)\tan40^\circ-\dfrac12\left(9.80\dfrac{\rm m}{\mathrm s^2}\right)\left(\dfrac{100\,\mathrm m^2}{v^2\cos^240^\circ}\right)

\implies\boxed{v\approx3.75\dfrac{\rm m}{\rm s}}

6 0
4 years ago
Assume that a satellite orbits mars 150km above its surface. Given that the mass of mars is 6.485 X 10^23kg, and the radius of m
Kisachek [45]
<span>3598 seconds The orbital period of a satellite is u=GM p = sqrt((4*pi/u)*a^3) Where p = period u = standard gravitational parameter which is GM (gravitational constant multiplied by planet mass). This is a much better figure to use than GM because we know u to a higher level of precision than we know either G or M. After all, we can calculate it from observations of satellites. To illustrate the difference, we know GM for Mars to within 7 significant figures. However, we only know G to within 4 digits. a = semi-major axis of orbit. Since we haven't been given u, but instead have been given the much more inferior value of M, let's calculate u from the gravitational constant and M. So u = 6.674x10^-11 m^3/(kg s^2) * 6.485x10^23 kg = 4.3281x10^13 m^3/s^2 The semi-major axis of the orbit is the altitude of the satellite plus the radius of the planet. So 150000 m + 3.396x10^6 m = 3.546x10^6 m Substitute the known values into the equation for the period. So p = sqrt((4 * pi / u) * a^3) p = sqrt((4 * 3.14159 / 4.3281x10^13 m^3/s^2) * (3.546x10^6 m)^3) p = sqrt((12.56636 / 4.3281x10^13 m^3/s^2) * 4.458782x10^19 m^3) p = sqrt(2.9034357x10^-13 s^2/m^3 * 4.458782x10^19 m^3) p = sqrt(1.2945785x10^7 s^2) p = 3598.025212 s Rounding to 4 significant figures, gives us 3598 seconds.</span>
8 0
3 years ago
First correct answer gets brainliest
maw [93]

Answer:

electrical energy transforming into sound energy in speaker

3 0
3 years ago
Read 2 more answers
How wide is the kuipter belt
Fynjy0 [20]
It's 30 AU extending from the ordit of Neptune to approximately 50 AU from the sun
Hopefully this help
7 0
3 years ago
Other questions:
  • “Blank” is a subtype of the continental climate.
    12·2 answers
  • Длина лодки=6 метров человек, масса которого в 2 раза меньше массы лодки переходит с носа на карму определить, на какое расстоян
    13·1 answer
  • Based on the concept of the wave-like nature of light, Huygens' theory of light __________ postulates that the more light was "b
    12·2 answers
  • What is a chloroplast in a animal cell
    12·2 answers
  • A block of mass m = 2.0 kg slides head on into a spring of spring constant k = 260 N/m. When the block stops, it has compressed
    13·1 answer
  • A diverging lens has a focal length of 23.9 cm. An object 2.1 cm in height is placed 100 cm in front of the lens. Locate the pos
    14·1 answer
  • A large sheet of charge has a uniform charge density of 9  μCm2. What is the electric field due to this charge at a point just
    6·1 answer
  • The wavelength of a moving particle is equal to divided by._____<br> .____
    13·2 answers
  • Plzz helpp mee!!!! plzzz
    10·1 answer
  • The atomic mass of sodium is 0.0230 kg/mole. How many moles are in 1.59 kg of sodium?
    14·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!