Question

Physics question, help please!

Answer 1

The change in potential energy when the block falls to ground is -480J.

The maximum change in kinetic energy of the ball is 480 J.

The initial kinetic energy of the ball is 0 J.

The final  kinetic energy of the ball is 0.148J.

The initial potential energy of the ball is 0.187 J.

The final  potential energy of the ball is 0 J.

The work done by the air resistance is 0.039 J.

Change in potential energy when the block falls to ground

ΔP.E = -mgh

ΔP.E = -Wh

ΔP.E = - 40 x 12

ΔP.E = -480 J

Maximum change in kinetic energy of the ball

ΔK.E = - ΔP.E

ΔK.E = - (-480 J)

ΔK.E = 480 J

Initial kinetic energy of the ball

K.Ei = 0.5mv²

where;

• v is zero since it is initially at rest

K.Ei = 0.5m(0) = 0

Final kinetic energy

K.Ef =  0.5mv²

K.Ef = 0.5(0.0091)(5.7)²

K.Ef = 0.148 J

Initial potential energy of the ball

P.Ei = mghi

P.Ei = 0.0091 x 9.8 x 2.1

P.Ei = 0.187 J

Final potential energy

P.Ef = mghf

P.Ef = 0.0091 x 9.8 x 0

P.Ef = 0

Work done by the air resistance

W = ΔE

W = P.E - K.E

W = 0.187 J - 0.148 J

W = 0.039 J

Learn more about potential energy here: brainly.com/question/1242059

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