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gregori [183]
3 years ago
14

How much oxygen molecules are there in a atom?

Chemistry
1 answer:
Inessa05 [86]3 years ago
7 0
There are 6.022 x 10 23 0 atoms in a mole of 0 atoms . there are 6.022 x 10 23 0 2 molecules in a mole of since you have 2 oxygen atoms in one molecule there are 2 x 6.022 x 10 23 0 atoms in a mole
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A chemical ________<br> is like a recipe for a chemical substance.
goldfiish [28.3K]

Answer:

iron

Explanation:

5 0
3 years ago
If there are 3 cats but they each die of different diseases one of heart fail, second of Brian tumor and 3rd of experiment gone
Snowcat [4.5K]

Answer:

none

Explanation:

It is given that there are 3 cats.

Each of the cats die with different diseases. One of cats died due to heart failure, the second cats died because of brain tumor and the third cat died due to an experiment gone wrong.

So there are none of the cats left out. All the cats died due to different reasons.

7 0
3 years ago
What is the ph (to nearest 0.01 ph unit) of a solution prepared by mixing 58.0 ml of 0.0179 m naoh and 60.0 ml of 0.0294 m ba(oh
Nina [5.8K]

Answer: -

12.59

Explanation: -

Strength of NaOH = 0.0179 M

Volume of NaOH = 58.0 mL = 58.0/1000 = 0.058 L

Number of moles = 0.0179 M x 0.058 L

= 1.04 x 10⁻³ mol

Mol of [OH⁻] given by NaOH = 1.04 x 10⁻³ mol

Strength of Ba(OH)₂ = 0.0294 M

Volume of Ba(OH)₂ = 60.0 mL = 60.0/1000 = 0.060 L

Number of moles = 0.0294 M x 0.060 L

= 1.76 x 10⁻³ mol

Mol of [OH⁻] given by Ba(OH)₂ =2 x 1.76 x 10⁻³ mol

Total [OH⁻] = 1.04 x 10⁻³ mol + 2 x 1.76 x 10⁻³ mol

= 4.56 x 10⁻³ mol

Total volume of the mixture = 58.0 + 60.0

= 118.0 mL

118.0 mL of the solution has 4.56 x 10⁻³ mol [OH⁻]

1000 mL of the solution has \frac{4.56 x 10-3 mol x 1000mL }{118 mL}

= 0.0386 mol

Using the relation

pOH = - log [OH-]

= - log 0.0386

= 1.41

Using the relation

pH + pOH = 14

pH = 14 - 1.41

= 12.59

5 0
3 years ago
The amount of I₃⁻(aq) in a solution can be determined by titration with a solution containing a known concentration of S₂O₂⁻³(aq
puteri [66]

Answer: 0.22 M

Explanation:

2S_2O_3^{2-}(aq)+I_3^-\rightarrow S_4O_6^{2-}(aq)+3I^-(aq)

Molarity of a solution is defined as the number of moles of solute dissolved per Liter of the solution.

Molarity=\frac{moles}{\text {Volume in L}}

moles of Na_2S_2O_3=Molarity\times {\text {Volume in L}}=0.440\times 0.025=0.011moles

Na_2S_2O_3\rightarrow 2Na^+S_2O_3^{2-}

Thus moles of S_2O_3^{2-} = 0.011

According to stoichiometry:  

2 moles of S_2O_3^{2-}(aq) require 1 mole of I_3^

Thus 0.011 moles of S_2O_3^{2-}(aq) require=\frac{1}{2}\times 0.011=5.5\times 10^{-3} moles of I_3^-

Thus Molarity of I_3^-=\frac{5.5\times 10^{-3}}{0.025L}=0.22M

Therefore, the molarity of I_3^- in the solution is 0.22 M

5 0
4 years ago
Whats 0.06 in scientific notations
melomori [17]
Move the decimal<span> so there is one non-zero digit to the left of the </span>decimal<span> point. The number of </span>decimal<span>places you move will be the exponent on the 10 . If the </span>decimal<span> is being moved to the right, the exponent will be negative. If the </span>decimal<span> is being moved to the left, the exponent will be positive.</span>
5 0
3 years ago
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