The question above can be solved by using this equation:
CAVA =CBVB
Where:
CA =Concentration of acid = 1.0 M
VA = Volume of acid = ?
CB = Concentration of base = 1.0 M
VB = Volume of base = 25 ml
VA = CBVB / CA
VA = [1 * 25] / 1 = 25 / 1 = 25
VA = 25 ml
Therefore, the volume of acid that is required to completely neutralize the base is 25 ml.<span />
Answer:
just replace the 9 mole with 3.68 g of Al .
I think it will help you.
The normal boiling point<span> of </span>ethanol<span> is 78.4 degrees C and, at thistemperature, </span>the vapor pressure<span> is 101325 Pascals (Pa) or 760manometric units
thx hope this helped bye.</span>
Answer:
A
Explanation:
it's the sum of the masses of all the atoms in the molecule
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