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lianna [129]
3 years ago
13

How much energy is absorbed when 15g of water at 100C boiled away?

Chemistry
1 answer:
creativ13 [48]3 years ago
4 0

Answer:

∴ Q = m·ΔHv = 15g x 540 cals/g = 8100 calories = 33,890 joules

Explanation:

Phase transition formula => Q = m·ΔHv

Q = amount of heat absorbed

ΔHv = Heat of vaporization = 540 cal/g = 25,594 joules/g at 100°C

m = mass of substance = 15 grams

∴ Q = m·ΔHv = 15g x 540 cals/g = 8100 calories = 33,890 joules

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A solution of hydrochloric acid of unknown concentration was titrated with 0.10 M NaOH. If a 100.-mL sample of the HCl solution
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<u>Answer:</u> The initial pH of the HCl solution is 3

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n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is NaOH.

We are given:

n_1=1\\M_1=?M\\V_1=100mL\\n_2=1\\M_2=0.10M\\V_2=1mL

Putting values in above equation, we get:

1\times M_1\times 100=1\times 0.10\times 1\\\\M_1=\frac{1\times 0.10\times 1}{1\times 100}=10M

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Putting values in above equation, we get:

pH=-\log (0.001)\\\\pH=3

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