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3 years ago

How much energy is absorbed when 15g of water at 100C boiled away?

Chemistry

1 answer:

creativ13 [48]3 years ago

4 0

Answer:

∴ Q = m·ΔHv = 15g x 540 cals/g = 8100 calories = 33,890 joules

Explanation:

Phase transition formula => Q = m·ΔHv

Q = amount of heat absorbed

ΔHv = Heat of vaporization = 540 cal/g = 25,594 joules/g at 100°C

m = mass of substance = 15 grams

∴ Q = m·ΔHv = 15g x 540 cals/g = 8100 calories = 33,890 joules

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2 years ago

Read 2 more answers

3. The following data of decomposition reaction of thionyl chloride (SO2Cl2) were collected at a certain temperature and the con

KonstantinChe [14]

Answer:

a) First-order.

b) 0.013 min⁻¹

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Explanation:

Hello,

In this case, on the attached document, we can notice the corresponding plot for each possible order of reaction. Thus, we should remember that in zeroth-order we plot the concentration of the reactant (SO2Cl2 ) versus the time, in first-order the natural logarithm of the concentration of the reactant (SO2Cl2 ) versus the time and in second-order reactions the inverse of the concentration of the reactant (SO2Cl2 ) versus the time.

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$m=\frac{ln(0.0768)-ln(0.0876)}{200min-100min} =-0.0013min^{-1}$

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