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3 years ago

The graph of h is a translation 4 units right and 1 unit down of the graph of f(x) = x2.

Mathematics

1 answer:

Galina-37 [17]3 years ago

3 0

Answer:

Step-by-step explanation:

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√70 is between which two numbers on the number line?

Leto [7]

Answer:

C) 8 and 9

Step-by-step explanation:

We know that 70 is between two perfect squares.

The square numbers 64 and 81 can help us solve this question.

64<70<81

We take square root to get:

$\sqrt{64} \: < \: \sqrt{70} < \sqrt{81}$

We simplify this to get:

$8 \: < \: \sqrt{70} \: < \: 9$

Therefore √70 is between 8 and 9.

The correct option is C.

6 0

3 years ago

Please Pleaseee help...will make the brainliest

snow_lady [41]

Answer:

A and F.

Explaination:

4 0

3 years ago

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Hugo wants to make a sandwich using wrap or baguette cheese or turkey mayonnaise or ketchup , list all the possible types of san

S_A_V [24]

Answer:

What subject is this

Step-by-step explanation:

6 0

3 years ago

What ere the coordinates of the point on the directed line segment from (-1,7) to (7,7) that partitions the segment into a ratio

djverab [1.8K]

Answer:

$(\frac{37}{11},\frac{77}{11} )$

Step-by-step explanation:

Given two points are (-1,7) and (7,7).

We are told to find a point which is in between them at a ratio of 6:5.

Formula for calculating a point at distance of ratio m:n is given by

$(\frac{mx2+nx1}{m+n} ,\frac{my2+ny1}{m+n} )$

where $(x1,y1),(x2,y2)$ are the inital and final points.

$(x1,y1)=(-1,7)\\\\(x2,y2)=(7,7)$

also m:n=6:5 ,

by substituting all the values we get,

$(\frac{6*7+5*-1}{11} ,\frac{6*7+5*7}{11} )$

$(\frac{37}{11},\frac{77}{11} )$

5 0

3 years ago

Suppose a parabola has an axis of symmetry at x=-5, a maximum height of 9, and passes through the point (-7,1). Write the equati

Nutka1998 [239]

the parabola has maximum at 9, meaning is a vertical parabola and it opens downwards.

it has a symmetry at x = -5, namely its vertex's x-coordinate is -5.

check the picture below.

so then, we can pretty much tell its vertex is at (-5 , 9), and we also know it passes through (-7, 1)

$\bf ~~~~~~\textit{parabola vertex form} \\\\ \begin{array}{llll} y=a(x- h)^2+ k\qquad \leftarrow \textit{using this one}\\\\ x=a(y- k)^2+ h \end{array} \qquad\qquad vertex~~(\stackrel{}{ h},\stackrel{}{ k}) \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \begin{cases} h=-5\\ k=9 \end{cases}\implies y=a[x-(-5)]^2+9\implies y=a(x+5)^2+9$

$\bf \textit{we also know that } \begin{cases} x=-7\\ y=1 \end{cases}\implies 1=a(-7+5)^2+9 \\\\\\ -8=a(-2)^2\implies -8=4a\implies \cfrac{-8}{4}=a\implies -2=a \\\\[-0.35em] ~\dotfill\\\\ ~\hfill y=-2(x+5)^2+9~\hfill$

7 0

3 years ago