Answer:
142 its the ans
Step-by-step explanation:
I'm not sure
Given:
The height h of an object after t seconds is

The height of a neighboring 50-foot tall building is modeled by the equation h=50.
The time (t) when the object will be at the same height as the building is found to be t = –2 and t = 5.
To find:
The statement which describes the validity of these solutions.
Solution:
We have,

Here, t is the time in seconds.
For t=-2,



For t=5,



So, the value of h is 50 at t=-2 and t=5.
We know that time is always positive so it cannot be negative value. It means t=-2 is not possible.
The solution t = 5 is the only valid solution to this system since time cannot be negative.
Therefore, the correct option is C.
There's a lot of information missing here, and the given list of choices is basically incomprehensible.
Suppose J (a, b) and K (c, d) are two points in the plane. We can trace out the line segment JK joining these points with the function
r(t) = (1 - t) (a, b) + t (c, d)
where 0 ≤ t ≤ 1.
Let P be the point that divides JK into line segments JP and PK having a length ratio of 2:5. Then JP is the point 2/7 of the way along JK, so that the coordinates of P are
P = r(2/7) = 5/7 (a, b) + 2/7 (c, d) = ((5a + 2c)/7, (5b + 2d)/7)
and in particular the x-coordinate of P is (5a + 2c)/7.
Answer:
0.75-0.5=0.25
Step-by-step explanation:
Subtract the minimum data value from the maximum data value to find the data range. In this case, the data range is 0.25 or 1/4.