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3 years ago

Help!!!!!!!!!!!!!!!!!!!!!

Mathematics

1 answer:

geniusboy [140]3 years ago

5 0

Answer:

It's D.

Step-by-step explanation:

The antenna revolves at 30 / 2 = 15 times / minute, so the one we need revolves ate 30 times per minute.

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1 1/5 divided by 3/10

MissTica

Answer: <em><u>4.</u></em> This is because 1 and 1/5 = 1.2 and 3/10 = 0.3 and 1.2 divided by 0.3 = 4. That's because 1.2 can be split into 4 equal groups and each group has 0.3.

4 0

3 years ago

Please help!! 15 points! I need 5 and 9 answered

Doss [256]

Answer:

B: Subtraction property of equality

4 0

3 years ago

Read 2 more answers

Consider the linear system of equations y=2/5x-1 and 2x-3y+1=0 graph the system of equations

nlexa [21]

We can see that the lines intersect at: (-5,-3)

Step-by-step explanation:

Given system of equations is:

$y = \frac{2}{5}x-1\ \ \ \ Eqn1\\2x-3y+1 = 0\ \ \ \ Eqn2$

Lets convert the second equation in the same form as the first equation

$2x-3y+1 = 0$

Adding 3y on both sides

$2x-3y+1+3y = 0+3y\\2x+1 = 3y\\3y= 2x+1$

Dividing both sides by 3

$\frac{3y}{3} = \frac{2x+1}{3}\\y = \frac{2}{3}x+\frac{1}{3}\\$

The graph of equation can be plotted using manual graphing or any online graphing calculator

We will use the Desmos online graphing calculator to graph the equations (Picture attached)

We can see that the lines intersect at: (-5,-3)

Keywords: Graphing, linear equations

Learn more about linear equations at:

#LearnwithBrainly

8 0

3 years ago

Find the length of the third side. If necessary, round to the nearest tenth. 16 23

Ksivusya [100]

Answer:

$\sqrt{273}$ units

Step-by-step explanation:

Use the Pythagorean Theorem: a^2 + b^2 = c^2

you have that a = 16 and c = 23, so:

16^2 + b^2 = 23^2

256 + b^2 = 529

b^2 = 273

b = $\sqrt{273}$

4 0

3 years ago

Write a well-structured MATLAB function procedure named Fnorm to calculate the Frobenius norm of an m × n matrix. ||A||f=∑mi=1∑n

coldgirl [10]

Answer:

Step-by-step explanation:

function Fn = Fnorm(A)

[r,c] = size(A);

sum = 0;

for i=1:r

for j=1:c

sum = sum + (A(i,j) * A(i,j));

end

Fn = sqrt(sum);

end

A = [5 7 9; 1 8 4; 7 6 2]

fprintf("The Frobenius norm of an m × n matrix is\n");

Fn = Fnorm(A)

=========================================================================================\

5 0

3 years ago