Answer:
Edouard > Berenica > Chdwick > Francesca = Avishka = Danya
Explanation:
The near and far vision points for a normal person are
Close view 25 cm
Far vision infinite
Let's use the constructor equation to raise the object to these points
Close vision
1 / f = 1 / o + 1 / i
where f is the focal length, or the distance to the object and i the distance to the image, in this case i must be 25cm for everyone, as this distance is on the same side as the object is negative, according to the optical sign convention
Avishka
The distance to the object is 40 cm
1 / f = 1 / 0.40 - 1 / 0.25 = -1.5
Focal power P is the inverse of the focal length in meters
P = 1 / f = -1.5 D
The vision for the far point is normal and therefore does not require correction P=0
Berenice
Distance to the object that can see o = 0.30 m
1 / f = P = 1 / o + 1 / i
P = 1 / 0.30 -1 / 0.25
P = -0.67 D
Far vision correction
o = 500cm = 5m
1 / f = 1 / o + 1 / i
P = 1/3 + 1 / inf
P = 0.33 D
Chadwick
Close point of view is normal, so does not require correction
Far vision point
1 / f = 1/5 + 1 / inf
P = 0.2 D
Danya
Has normal vision does not require glasses
P = 0
Edouard
Close view point
o = 80cm = 0.80m
1 / f = 1 / o + 1 / i
1 / f = 1 / 0.80 - 1 / .25
P = -2.75 D
Far vision point
o = 200cm = 2m
P = 1 / f = ½ + 1 / onf
P = 0.5 D
Francesca
Close vision point
o = 50 cm = 0.50 m
1 / f = 1 / 0.5 - 1 / .25
1 / f = -2 D
Normal far vision point
We write in summary the focal power for each person and each point
Person Near point Far point
Avishka -1.5D 0
Berenice -0.67D 0.33D
Chadwick 0 0.2D
Danya 0 0
Edouard -2.75D 0.5D
Francesca -2D 0
In order of the lenses required from highest to lowest we have
, por teh near ponint myopia
Edouard> Francesca> Avishka> Berenice> Chanwick> Danya
Para el point of the far vision (hyperopic)
Edouard > Berenica > Chdwick > Francesca = Avishka = Danya
