All categories

4 years ago

Please help me!!! I have to write 2 pages on this. And I need some help:(!! Due soon!!

Physics

1 answer:

Zolol [24]4 years ago

8 0

Answer:

No matter, what there is always the same amount of energy in the universe!

Explanation:

That is essentially what the Law of Conservation of Energy states, however, this passage. Now I don't really have an in-depth view of what your requirements are, however, the idea is that energy cannot be destroyed or created; it can only be transformed. You have most likely learned about energy transformations: potential to kinetic (being a broad category). If potential energy goes down (for an object), kinetic energy for the object goes up. The Ramsey Box is essentially stating that the less you train, the more you will suck. The total mechanical energy stays the same, and goes up or down together. The less hard work, the more failure. The more hard work, the less failure. Comment if you want more info. I'm in 8th grade too btw:)

You might be interested in

A 0.8 kg object displaces 500 mL of water. What is its specific gravity?

Airida [17]

The specific gravity is how the density of the object compares to the density of water. Water's density is 1gram per milliliter. We just need to figure out the density of the object.

The object is .8 kg and it displaces 500mL of water, so the density is the mass divided by the volume. Since the density of water is given in grams, we have to convert the objects mass from kg to g and then we can get the density.

.8kg * 1000g/kg = 800 grams

So

800g/500ml = 1.6grams/mL this is the density.

So divide the density of your object by the density of water, which is 1g/mL, you get 1.6 as the specific gravity. This means the object is 1.6 times more dense than water.

8 0

4 years ago

How high is a 3 kg object that has 3000 j of potential energy

Mila [183]

Using the formula $z=\frac{E}{m*g}$

$z=\frac{3000}{3*9.80665}$

$z=101.97$ meters

8 0

3 years ago

Before 1960, people believed that the maximum attainable coefficient of static friction for an automobile tire on a roadway was

Eduardwww [97]

Answer:

4.18

Explanation:

Givens

The car's initial velocity $v_{i}$ = 0 and covering a distance Δx = 1/4 mi = 402.336 m in a time interval t = 4.43 s.

Knowns

We know that the maximum static friction force is given by:

$f_{s_max} =$ μ_s*n (1)

Where μ_s is the coefficient of static friction and n is the normal force.

Calculations

(a) First, we calculate the acceleration needed to achieve this goal by substituting the given values into a proper kinematic equation as follows:

Δx= $v_{i} +\frac{1}{2} at^2$

a=41 m/s

This is the acceleration provided by the engine. Applying Newton's second law on the car, so in equilibrium, when the car is about to move, we find that:

$f_{y}=n-mg=0\\ n=mg\\f_{x}=F-f_{s,max} =0\\ f_{s,max}=F=ma\\$

Substituting (3) into (1), we get:

$f_{s,max}=$ μ_s*m*g

Equating this equation with (4), we get:

ma= μ_s*m*g

μ_s=a/g

=4.18

3 0

4 years ago

A 50 V source is attached to a 9 Ohm light bulb, a 15 Ohm resistor, and a 17 Ohm resistor. What is the total resistance in the c

4vir4ik [10]

Answer:

Explanation:

4 0

3 years ago

What statement best describes what it means to maximize your efforts in sports?

Yuliya22 [10]

What statement best describes what it means to maximize your efforts in sports?

D.none of the above

5 0

3 years ago