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4 years ago

Please help me!!! I have to write 2 pages on this. And I need some help:(!! Due soon!!

Physics

1 answer:

Zolol [24]4 years ago

8 0

Answer:

No matter, what there is always the same amount of energy in the universe!

Explanation:

That is essentially what the Law of Conservation of Energy states, however, this passage. Now I don't really have an in-depth view of what your requirements are, however, the idea is that energy cannot be destroyed or created; it can only be transformed. You have most likely learned about energy transformations: potential to kinetic (being a broad category). If potential energy goes down (for an object), kinetic energy for the object goes up. The Ramsey Box is essentially stating that the less you train, the more you will suck. The total mechanical energy stays the same, and goes up or down together. The less hard work, the more failure. The more hard work, the less failure. Comment if you want more info. I'm in 8th grade too btw:)

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Which item has the most carbohydrates? 1.Soda 2.Cereal 3.Wheat bread 4.Rice

Amiraneli [1.4K]

Answer: soda

Explanation:

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3 years ago

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An atom of uranium 238 emits an alpha particle (an atom of He) and recoils with a velocity of 1.895 * 10^ 5 m/sec . With velocit

lora16 [44]

Answer: The velocity of released alpha particle is $1.127\times 10^7m/s$

Explanation:

According to law of conservation of momentum, momentum can neither be created nor be destroyed until and unless, an external force is applied.

For a system:

$m_1v_1=m_2v_2$

where,

$m_1\text{ and }v_1$ = Initial mass and velocity

$m_2\text{ and }v_2$ = Final mass and velocity

We are given:

$m_1=238u\\v_1=1.895\times 10^{5}m/s\\m_2=4u\text{ (Mass of }\alpha \text{ -particle)}\\v_2=?m/s$

Putting values in above equation, we get:

$238\times 1.895\times 10^5=4\times v_2\\\\v_2=\frac{238\times 1.895\times 10^5}{4}=1.127\times 10^7m/s$

Hence, the velocity of released alpha particle is $1.127\times 10^7m/s$

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3 years ago

Important minerals such as copper are found in what?

adoni [48]

It can be found in granitic and basaltic rock.

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4 years ago

A cosmic ray proton moving toward the Earth at 3.5x 10^7 ms experiences a magnetic force of 1.65x 10^-16 N. What is the strength

Step2247 [10]

Answer:

Magnetic field, $B=4.16\times 10^{-5}\ T$

Explanation:

It is given that,

Velocity of proton, $v=3.5\times 10^7\ m/s$

Magnetic force, $F=1.65\times 10^{-16}\ N$

Charge of proton, $q=1.6\times 10^{-19}\ C$

We need to find the strength of the magnetic field if there is a 45° angle between it and the proton's velocity. The formula for magnetic force is given by :

$F=qvB\ sin\theta$