The generic equation for a reaction between an acid and water is

When an acid "reacts" with water, water acts as the base that accepts the proton (H+) from the acid. The remaining ion that is formed after the acid has donated its proton is called the conjugate base (

), and the conjugate acid-base pair is

-

.
Hydrogen sulfate (

) is an ion from sulfuric acid. It is still an acid in itself and can "react" with water ((

) to form the sulfate (

) and hydronium (

)ions.

Based on the previous discussion,

is identified to be the conjugate of the acid

.
Thus, the conjugate acid-base pair is
.
Scientists often repeat one or more steps several times.
:<span> </span><span>4 HCl + MnO2 → MnCl2 + 2 H2O + Cl2
(33.7 g MnO2) / (86.93691 g MnO2/mol) = 0.38764 mol MnO2
(45.3 g HCl) / (36.4611 g HCl/mol) = 1.2424 mol HCl
(a)
1.2424 moles of HCl would react completely with 1.2424 x (1/4) = 0.3106 mole of MnO2, but there is more MnO2 present than that, so MnO2 is in excess and HCl is the limiting reactant.
(b)
(1.2424 mol HCl) x (1 mol Cl2 / 4 mol HCl) x (70.9064 g Cl2/mol) = 22.0 g Cl2
(c)
(77.7% of 22.0 g Cl2) = 17.1 g Cl2</span>
14 carbon atoms do the 14CO2 used to synthesize malonyl-COA from acetyl-CoA appear in palmitate.
Acetyl-CoA is carboxylated into malonyl-CoA by the acetyl-CoA carboxylase enzyme. The joining of one acetyl-CoA molecule and one bicarbonate molecule requires energy from ATP.
Malonyl coenzyme A: acyl carrier protein transacylase is an enzyme that uses malonyl-CoA in the production of fatty acids (MCAT).
The highly controlled acetyl-CoA carboxylase (ACC) in the cytoplasm produces malonyl-CoA by carboxylation acetyl-CoA in biotin and ATP-dependent manner. Acetyl-CoA carboxylase is an enzyme that changes acetyl-CoA into malonyl-CoA. Malonyl-ACP is created when the malonyl group is added to an acyl carrier protein.
A condensation reaction between malonyl-ACP and acetyl-CoA results in acyl-ACP and the simultaneous release of CO2.
Learn more about acetyl-CoA here brainly.com/question/13063128
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Answer : The value of ΔH for this reaction is, -1516 kJ/mol
Explanation :
First we have to calculate the moles of 



Now we have to calculate the ΔH for this reaction.
As, 2.5 mole of
react to gives heat = -3790 kJ
So, 1 mole of
react to gives heat = 
= -1516 kJ/mol
Therefore, the value of ΔH for this reaction is, -1516 kJ/mol