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2 years ago

5

Given the graph below and the equation y = 4x, determine which function has the greatest rate of growth?

1 answer:

Marizza181 [45]2 years ago

4 0

Answer:

Step-by-step explanation:

A slope of 4 has a greater rate of growth than a graph with a slope of 1

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Hellpppp meee pleaseee:/

Harman [31]

1. convert to improper fractions

3/2 x -5/4= -15/8= -1 7/8

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3 years ago

Write an equation in standard form that has a slope of - and a y-intercept of -2.

Setler79 [48]

Answer:

y= 3x-2

Step-by-step explanation:

standard form

y= mx + c

c represents y intercept

m represents slope or gradient

y= 3x-2

The slope is 3 and the y intercept in -2

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3 years ago

A loaf of bread has a volume of 2270 cm3 and a mass of 454 g. What is the density of the bread?

svlad2 [7]

Density = Mass / Volume

Density = 454 / 2270

Density = 0.2 g/cm^3

6 0

3 years ago

Read 2 more answers

Which equation represents a graph with a vertex at (–3, 2)?

lesya [120]

<u>We will proceed to find the equations in the vertex form in each case</u>

<u>Part a)</u> $y= 4x^{2}+24x+38$

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$y-38= 4x^{2}+24x$

Factor the leading coefficient

$y-38= 4(x^{2}+6x)$

Complete the square. Remember to balance the equation by adding the same constants to each side

$y-38+36= 4(x^{2}+6x+9)$

$y-2= 4(x+3)^{2}$

$y= 4(x+3)^{2}+2$

<u>the vertex is the point $(-3,2)$ </u>

<u>Part b)</u> $y=4x^{2}-24x+38$

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$y-38= 4x^{2}-24x$

Factor the leading coefficient

$y-38= 4(x^{2}-6x)$

Complete the square. Remember to balance the equation by adding the same constants to each side

$y-38+36= 4(x^{2}-6x+9)$

$y-2= 4(x-3)^{2}$

$y= 4(x-3)^{2}+2$

<u>the vertex is the point $(3,2)$ </u>

<u>Part c) </u> $y=4x^{2}+12x+2$

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$y-2= 4x^{2}+12x$

Factor the leading coefficient

$y-2= 4(x^{2}+3x)$

Complete the square. Remember to balance the equation by adding the same constants to each side

$y-2+9= 4(x^{2}+3x+2.25)$

$y+7= 4(x+1.5)^{2}$

$y= 4(x+1.5)^{2}-7$

<u>the vertex is the point $(-1.5,7)$ </u>

<u>Part d)</u> $y=4x^{2}+16x+13$

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$y-13= 4x^{2}+16x$

Factor the leading coefficient

$y-13= 4(x^{2}+4x)$

Complete the square. Remember to balance the equation by adding the same constants to each side

$y-13+16= 4(x^{2}+4x+4)$

$y+3= 4(x+2)^{2}$

$y= 4(x+2)^{2}-3$

<u>the vertex is the point $(-2,-3)$ </u>

therefore

<u>the answer is </u>

$y= 4x^{2}+24x+38$

3 0

3 years ago

Read 2 more answers

Over what interval is the function in this graph constant?

AfilCa [17]

Answer:

A

Step-by-step explanation:

as this the graph hits the X axis before -5 and before 5

Give BRAINLIEST PLZ

4 0

3 years ago