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Minchanka [31]
3 years ago
5

Given the graph below and the equation y = 4x, determine which function has the greatest rate of growth?

Mathematics
1 answer:
Marizza181 [45]3 years ago
4 0

Answer:

Step-by-step explanation:

A slope of 4 has a greater rate of growth than a graph with a slope of 1

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When you graph a system of equations what are the three possible outcomes?
siniylev [52]

Answer:

i think its a beaner

Step-by-step explanation:

5 0
3 years ago
Help help help thanks
Dmitry [639]

Answer: a=2/5b + 1/5c (I may have answered your question but idk if I did)

Step 1: Add -4a to both sides.

9a−2b+−4a=4a+c+−4a

5a−2b=c

Step 2: Add 2b to both sides.

5a−2b+2b=c+2b

5a=2b+c

Step 3: Divide both sides by 5.

5a/5=2b+c/5

a=2/5b+1/5c

7 0
3 years ago
The legs of an isosceles triangle measure ( 2 x^4 + 2 x − 1 ) units each. The perimeter of the triangle is ( 5 x^4 − 2 x^3 + x −
nirvana33 [79]

Answer:

The base is x^4 -2x^3 -3x-1

Step-by-step explanation:

We know the perimeter of a triangle is the sum of the three sides

P = s1+s2+s3

We know the perimeter is  5 x^4 − 2 x^3 + x − 3

and two of the legs are 2 x^4 + 2 x − 1  since it is an isosceles triangle

P = 2s1 + s3

Subtract 2s1 from each side

P-2s1 =2s1 +s3 -2S1

P -2s1 =s3

Substituting what we know

5 x^4 − 2 x^3 + x − 3 - 2(2 x^4 + 2 x − 1) = s3

Distribute the -2

5 x^4 − 2 x^3 + x − 3 - 4 x^4 -4 x + 2 = s3

Combine like terms

5 x^4-4x^4 − 2 x^3 + x  -4 x -3+ 2 = s3

x^4 -2x^3 -3x-1 =s3

The base is x^4 -2x^3 -3x-1

5 0
4 years ago
How many positive integers $n$ satisfy $127 \equiv 7 \pmod{n}$? $n=1$ is allowed.
Svetllana [295]
Naturally, any integer n larger than 127 will return 127\equiv127\mod n, and of course 127\equiv0\mod127, so we restrict the possible solutions to 1\le n.

Now,

127\equiv7\mod n

is the same as saying there exists some integer k such that

127=nk+7

We have

\implies 120=nk

which means that any n that satisfies the modular equivalence must be a divisor of 120, of which there are 16: \{1,2,3,4,5,6,8,10,12,15,20,24,30,40,60,120\}.

In the cases where the modulus is smaller than the remainder 7, we can see that the equivalence still holds. For instance,

127=21\cdot6+1\iff127\equiv1\equiv7\mod6

(If we're allowing n=1, then I see no reason we shouldn't also allow 2, 3, 4, 5, 6.)
5 0
4 years ago
A. 2<br> B. 3<br> C. 12<br> D. 15
satela [25.4K]

count the numbers next to the 5, 6 & 7 = 10. then there are 2 numbers next to 8 less than 2

 so 10 +2 = 12 students

5 0
3 years ago
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