Answer:
i think its a beaner
Step-by-step explanation:
Answer: a=2/5b + 1/5c (I may have answered your question but idk if I did)
Step 1: Add -4a to both sides.
9a−2b+−4a=4a+c+−4a
5a−2b=c
Step 2: Add 2b to both sides.
5a−2b+2b=c+2b
5a=2b+c
Step 3: Divide both sides by 5.
5a/5=2b+c/5
a=2/5b+1/5c
Answer:
The base is x^4 -2x^3 -3x-1
Step-by-step explanation:
We know the perimeter of a triangle is the sum of the three sides
P = s1+s2+s3
We know the perimeter is 5 x^4 − 2 x^3 + x − 3
and two of the legs are 2 x^4 + 2 x − 1 since it is an isosceles triangle
P = 2s1 + s3
Subtract 2s1 from each side
P-2s1 =2s1 +s3 -2S1
P -2s1 =s3
Substituting what we know
5 x^4 − 2 x^3 + x − 3 - 2(2 x^4 + 2 x − 1) = s3
Distribute the -2
5 x^4 − 2 x^3 + x − 3 - 4 x^4 -4 x + 2 = s3
Combine like terms
5 x^4-4x^4 − 2 x^3 + x -4 x -3+ 2 = s3
x^4 -2x^3 -3x-1 =s3
The base is x^4 -2x^3 -3x-1
Naturally, any integer

larger than 127 will return

, and of course

, so we restrict the possible solutions to

.
Now,

is the same as saying there exists some integer

such that

We have

which means that any

that satisfies the modular equivalence must be a divisor of 120, of which there are 16:

.
In the cases where the modulus is smaller than the remainder 7, we can see that the equivalence still holds. For instance,

(If we're allowing

, then I see no reason we shouldn't also allow 2, 3, 4, 5, 6.)
count the numbers next to the 5, 6 & 7 = 10. then there are 2 numbers next to 8 less than 2
so 10 +2 = 12 students