What is one basic need that both monkey and a tree have in common
2 answers:
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Answer:
cm
Explanation:
= separation between the slits = 2783 x 10⁻⁹ m
= wavelength of coherent light = 644 nm = 644 x 10⁻⁹ m
= Distance of the screen = 6 cm = 0.06 m
= Position of nth bright fringe
Position of nth bright fringe is given as
for n = 2
m
for n = 4
m
Distance between 4th and 2nd bright fringes is given as
cm
Answer:
the force exerted on the foot by the tibia would be 2975 N
Explanation:
Given the data in the question;
To maintain equilibrium between the foot and the ball vertically, the addition normal normal force (750 N) and the tension in the Achilles tendon
(2225 N) must be equal to the force exerted on the foot by the tibia;
so
| | + |
| = |
|
so force exerted on the foot by the tibia will be;
| | = |
| + |
|
so we substitute IN OUR VALUES
| | = 750 N + 2225 N
| | = 2975 N
Therefore, the force exerted on the foot by the tibia would be 2975 N
Answer:
82.76m
Explanation:
In order to find the distance of the steel ring to the ground, when its temperature has raised by 1°C, you first calculate the radius of the steel tube before its temperature increases.
You use the formula for the circumference of the steel ring:
(1)
C: circumference of the ring = 40000 km = 4*10^7m (you assume the circumference is the length of the steel tube)
you solve for r in the equation (1):
Next, you use the following formula to calculate the change in the length of the tube, when its temperature increases by 1°C:
(2)
L: final length of the tube = ?
Lo: initial length of the tube = 4*10^7m
ΔT = change in the temperature of the steel tube = 1°C
α: thermal coefficient expansion of steel = 13*10^-6 /°C
You replace the values of the parameters in the equation (2):
With the new length of the tube, you can calculate the radius of a ring formed with the tube. You again solve the equation (1) for r:
Finally, you compare both r and r' radius:
r' - r = 6,366,280.484m - 6,366,197.724m = 82.76m
Hence, the distance to the ring from the ground is 82.76m