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borishaifa [10]

3 years ago

12

A football team lost 9 yards during a play. The team had a combined gain or loss of 0 yards after the next play. What integer re

presents the yards gained or lost on the next play? Show this on the number line.

1 answer:

Natalija [7]3 years ago

8 0

Answer:

_____________

The integer is 0

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Find the measure of the missing angles.<br> 62°<br> b\co

tiny-mole [99]

The measures of angles B and C are 118° and 62°, respectively.

<h3>What are the measures of two missing angles generated by the intersection of two lines?</h3>

A system of three angles is generated by two lines intersecting each other. In accordance with Euclidean geometry, angle C is opposite to the angle with measure 62° and angle B is supplementary to the same angle.

When two angles are opposite, then both have the same measure, and when two angles are supplementary, then the sum of their measures equals 180°. Therefore, the measures of angles B and C are 118° and 62°, respectively.

To learn more on angles: brainly.com/question/7116550

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8 0

2 years ago

If $400 is invested at the rate of 6% for one year, what will be the total value of the investment (the amount)? $42.40 $424.00

ValentinkaMS [17]

The total value would be the amount he put in plus the amount he earns in interest. The answer should be 424

8 0

4 years ago

Read 2 more answers

A vertical cylinder is leaking water at a rate of 4m3/sec. If the cylinder has a height of 10m and a radius of 2m, at what rate

Lyrx [107]

Answer:

Therefore the rate change of height is $\frac{1}{\pi}$ m/s.

Step-by-step explanation:

Given that a vertical cylinder is leaking water at rate of 4 m³/s.

It means the rate change of volume is 4 m³/s.

$\frac{dV}{dt}=4 \ m^3/s$

The radius of the cylinder remains constant with respect to time, but the height of the water label changes with respect to time.

The height of the cylinder be h(say).

The volume of a cylinder is $V=\pi r^2 h$

$=( \pi \times 2^2\times h)\ m^3$

$\therefore V= 4\pi h$

Differentiating with respect to t.

$\frac{dV}{dt}=4\pi \frac{dh}{dt}$

Putting the value $\frac{dV}{dt}$

$\Rightarrow 4\pi \frac{dh}{dt}=4$

$\Rightarrow \frac{dh}{dt}=\frac{4}{4\pi}$

$\Rightarrow \frac{dh}{dt}=\frac{1}{\pi}$

The rate change of height does not depend on the height.

Therefore the rate change of height is $\frac{1}{\pi}$ m/s.

3 0

3 years ago

What is 3/18 written in simplest form explain how you found your answer

GaryK [48]

1/6 because 3 goes into 3 once, and 3 goes into 18 6 times. So the fraction is 1/6

7 0

3 years ago

Read 2 more answers

A large truck has two fuel tanks, each with a capacity of 150 gallons. Tank 1 is half full, and Tank 2 is empty.

12345 [234]

Answer:

1) $G(t) = 75 + \frac{23}{4}t\\$

2) After 8 minutes delivering fuel the tanks will have 121 gallons of fuel

Step-by-step explanation:

1) For generating the equation we have to take into account that in the tanks there is a initial volume of fuel that corresponds to 75 gallons, as it is stated that tank one is half full. As the capacity for tank 1 is of 150 gallons, half of the tank equals to:

$\frac{150}{2} = 75 gallons$

Now we have to convert the rate of delivery that is expressed as a mixed number to an improper fraction so:

$5\frac{3}{4} = \frac{(5x4)+3}{4} = \frac{23}{4}$

Then the pumping rate is of 23/4 gallons per minute, to get how many gallons are in the tank we just need to multiply this rate by the time in minutes, and as there is an initial volume we have to add it, so we have the following equation:

$G(t) = 75 + \frac{23}{4}t\\$

2) To know how much fuel is in the tank after 8 minutes we have to replace this time in the previous equation so we have

$G(t) = 75 + \frac{23}{4}t\\G(8) = 75 + \frac{23}{4}(8)\\G(8) = 75 + 23(2)\\G(8) = 75 + 46\\G(8) = 121 gallons$

After 8 minutes delivering fuel the tanks will have 121 gallons of fuel

8 0

3 years ago