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3 years ago

Please answer correctly !!!!!! Will mark brianliest answer !!!!!!!!!!

Mathematics

1 answer:

Lina20 [59]3 years ago

6 0

Answer:

see below

Step-by-step explanation:

g(x) = (x² - 2 * 1/2 x) - 6

= (x - 0.5)² - 0.25 - 6

= 1(x - 0.5)² - 6.25

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Mikhael wanted to rewrite the conversion factor "1 yard ≈ 0.914 meter" to create a conversion factor to convert meters to yards.

Nataly [62]

Answer:

$1\ meter = 1.094\ yard$

Step-by-step explanation:

Given

$1\ yard = 0.914\ meter$

Required

Create a convert meter to yard expression

$1\ yard = 0.914\ meter$

Divide both sides by 0.914

$\frac{1\ yard}{0.914} = \frac{0.914\ meter}{0.914}$

$\frac{1\ yard}{0.914} = 1\ meter$

$1.09409190372\ yard = 1\ meter$

$1\ meter = 1.09409190372\ yard$

$1\ meter = 1.094\ yard$ --- approximated

6 0

2 years ago

What is the value of x?<br><br> Enter your answer in the box.<br> units<br><br> ___Units

kotykmax [81]

The value of x is 28 .

<h3>What is a Triangle ?</h3>

A triangle is a polygon with three sides , three angles and three vertices.

According to the Proportionality Theorem

When a line is parallel to one side and intersects the other lines at two different points then it divides both the line in similar ratio.

As in the given figure DC is parallel to AP ,

then RD : DP = RC:CA

42:15 = x: 10

42/15 = x / 10

x = 42 * 10 /15

x = 28

Therefore the value of x is 28 .

To know more about Triangle

brainly.com/question/2773823

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7 0

2 years ago

when you divide a fraction less than 1 by a whole number greater than 1, is the quotient less than, greater than, or equal to th

ratelena [41]

Answer:

less than

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

Use the Trapezoidal Rule, the Midpoint Rule, and Simpson's Rule to approximate the given integral with the specified value of n.

Vera_Pavlovna [14]

Split up the integration interval into 4 subintervals:

$\left[0,\dfrac\pi8\right],\left[\dfrac\pi8,\dfrac\pi4\right],\left[\dfrac\pi4,\dfrac{3\pi}8\right],\left[\dfrac{3\pi}8,\dfrac\pi2\right]$

The left and right endpoints of the $i$ -th subinterval, respectively, are

$\ell_i=\dfrac{i-1}4\left(\dfrac\pi2-0\right)=\dfrac{(i-1)\pi}8$

$r_i=\dfrac i4\left(\dfrac\pi2-0\right)=\dfrac{i\pi}8$

for $1\le i\le4$ , and the respective midpoints are

$m_i=\dfrac{\ell_i+r_i}2=\dfrac{(2i-1)\pi}8$

Trapezoidal rule

We approximate the (signed) area under the curve over each subinterval by

$T_i=\dfrac{f(\ell_i)+f(r_i)}2(\ell_i-r_i)$

so that

$\displaystyle\int_0^{\pi/2}\frac3{1+\cos x}\,\mathrm dx\approx\sum_{i=1}^4T_i\approx\boxed{3.038078}$

Midpoint rule

We approximate the area for each subinterval by

$M_i=f(m_i)(\ell_i-r_i)$

so that

$\displaystyle\int_0^{\pi/2}\frac3{1+\cos x}\,\mathrm dx\approx\sum_{i=1}^4M_i\approx\boxed{2.981137}$

Simpson's rule

We first interpolate the integrand over each subinterval by a quadratic polynomial $p_i(x)$ , where

$p_i(x)=f(\ell_i)\dfrac{(x-m_i)(x-r_i)}{(\ell_i-m_i)(\ell_i-r_i)}+f(m)\dfrac{(x-\ell_i)(x-r_i)}{(m_i-\ell_i)(m_i-r_i)}+f(r_i)\dfrac{(x-\ell_i)(x-m_i)}{(r_i-\ell_i)(r_i-m_i)}$

so that

$\displaystyle\int_0^{\pi/2}\frac3{1+\cos x}\,\mathrm dx\approx\sum_{i=1}^4\int_{\ell_i}^{r_i}p_i(x)\,\mathrm dx$

It so happens that the integral of $p_i(x)$ reduces nicely to the form you're probably more familiar with,

$S_i=\displaystyle\int_{\ell_i}^{r_i}p_i(x)\,\mathrm dx=\frac{r_i-\ell_i}6(f(\ell_i)+4f(m_i)+f(r_i))$

Then the integral is approximately

$\displaystyle\int_0^{\pi/2}\frac3{1+\cos x}\,\mathrm dx\approx\sum_{i=1}^4S_i\approx\boxed{3.000117}$

Compare these to the actual value of the integral, 3. I've included plots of the approximations below.

3 0

3 years ago

Shankar has decided to train to be a Carbucks Barrista. Being young and inexperienced, for every order he makes a mistake in mak

astra-53 [7]

Answer:

Step-by-step explanation:

Since each trial is independent of the other

no of mistakes he does is binomial with p = 1/3

a) the probability that he makes no mistakes on his first 10 orders but the 11th order is a mistake

= $(\frac{2}{3}) ^{10} *\frac{1}{3}\\=\frac{2^{10} }{3^{11} }$

b) Prob that shanker quits = P(Shankar does I one mistake and Fran does not do the first one)+Prob (Shanker does mistake in the II one while Fran does both right)

= $\frac{1*5}{3*6} +\frac{2}{3} \frac{1}{3}(\frac{5}{6})^2 =\frac{5}{18} +\frac{50}{216} \\=\frac{55}{108}$

6 0

3 years ago