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2 years ago

Which expression is equivalent to 1/3/?

Mathematics

1 answer:

Rzqust [24]2 years ago

3 0

Answer:

2\5,3\7,4\9,5\11

Thats the answer

You might be interested in

Find the derivative of f(x) = 8x^2 + 11x at x = 7.

sleet_krkn [62]

Thank you for posting your question here at brainly. Feel free to ask more questions.

f′(x)=2∗(8x(2−1))+1∗11x(1−1)

which is

f′(x)=16x+11

then let x = 7 gives us

f′(7)=123

Hope my answer would be a great help for you.

6 0

2 years ago

Jacob walks 1.5 miles north. He turns and walks 0.8 miles west. How far is he from his starting point?

Flura [38]

Answer:

1.7 miles

Step-by-step explanation:

Given that,

Jacob walks 1.5 miles north.

He turns and walks 0.8 miles west.

We need to find how far is he from his starting point. Let he is at a distance of x miles from the starting point. It can be calculated as follows :

$x=\sqrt{1.5^2+0.8^2} \\\\x=1.7\ \text{miles}$

Hence, he is 1.7 miles from his starting point.

7 0

2 years ago

3. What is the solution to the equation 3x = 15? Express the

ivanzaharov [21]

Answer:

x=2.4650

Step-by-step explanation:

I assume that you mean $3^x=15$

so let s use the ln() function

$ln(3^x)= xln(3)=ln(15)$

so x = ln(15)/ln(3)

x = 2.4650

4 0

2 years ago

Find the first term and the common ratio third term =6 and seventh term= 96

mamaluj [8]

Answer:

First term a₁ = 3/2 and common ratio r = 2

Step-by-step explanation:

We need to find the first term and common ratio while we are given third term = 6 and seventh term = 96

Since common ratio is required so, the sequence is geometric sequence

The formula used is: $a_n= a_1r^{n-1}$

We are given: third term = 6 i,e

$a_3=a_1r(3-1)\\6=a_1r^2----eq(1)$

Seventh term = 96

$a_7=a_1r(7-1)\\96=a_1r^6----eq(2)$

Dividing eq(2) and eq(3)

$\frac{96}{6}=\frac{a_1r^6}{a1r2}\\16=\frac{r^6}{r^2}\\16=r^{6-2}\\=> r^4=16\\Taking \ fourth \ root\\ r=2,-2,2i,-2i\\ \ We \ will \ consider \ only \ positive \ value \ of \ r \ i.e \ \textbf{ r= 2}$

So, Common Ratio r = 2

Finding First term using eq(1)

$a_3=a_1r^2\\6=a_1(2)^2\\6=a_1(4)\\a_1= \frac{6}{4}\\a_1= \frac{3}{2}$

So, First term a₁ = 3/2 and common ratio r = 2

6 0

2 years ago

What's 8 thousands 2 tens divided by 10

kobusy [5.1K]

8,020 divided by 10 is 802.
Hope this helps!

5 0

2 years ago

Read 2 more answers