Question

A man drives from home at 10.45 to the airport which is 325 km away.He travels at an average speed of 50km/h. a) Find his arrival time at the airport. b)After sending of his friend,the man drives back at 18 35 and arrives home at 23 10. Write down the time taken for the return journey.​

Answer 1

☸ Solution:

We have,

• Departing time = 10 : 45 hours
• Distance between home and airport = 325 km
• Average speed = 50 km/h

Finding time taken by the man,

⇛ Average speed = Total Distance/Total time

⇛ Total time = Total Distance/Average speed$.$

⇛ Total time = 325 km/50 km/h

⇛ Total time = 6.5 h (6 hrs 30 mins)

(a) Total Time duration,

⇛ Total Time = Reaching Time - Departing time

⇛ 6.5 h = Reaching Time - 10 : 45 hours

⇛ Reaching Time = 17 : 15 hours ( 5 : 15 pm)

(b) Finding time taken in return,

• Departing time = 18 : 35 hours
• Reaching time = 23 : 10 hours

Total time duration,

⇛ Total Time = Reaching Time - Departing time

⇛ Total Time = 23 : 10 hours - 18 : 35 hours

⇛ Total Time = 22 : 70 hours - 18 : 35 hours

⇛ Total time = 4 : 35 hours

☕ Hence, solved !!

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