Answer:
The answer is C.
Step-by-step explanation:
Given the line segment ST. we have to give the instruction to construct the perpendicular bisector of line ST.
So to construct the perpendicular bisector of line our first step is to place the compass at one end of line and then adjust the compass more than half of line segment and draw the arc on each side of segment.
After that Keeping the same compass width, draw arcs from other end of line. Place scale where the arcs intersect, and draw the line segment.
So, the correct match is option C ) Place the compass point on point S and open the compass so that the pencil point is on the segment, but closer to point T than to point S. Draw an arc on each side of segment.
The sentence says the speed can be maintained for no more than 1640 feet.
The "no more" means 1640 feet or less ,so the equation would be d is less than or equal to 1640.
The correct equation is A.
Two lines intersect in one point.
Start with the parent function f(x) = x³
Notice the function f(x) = (x - 4)³ that a value '4' is subtracted from 'x' ⇒ This means the function f(x) is translated four units to the right.
Then the function f(x) = ¹/₂ (x - 4)³, the function (x - 4)³ is halved vertically ⇒ Half the y-coordinate
Then the function f(x) = ¹/₂ (x - 4)³ + 5 that a value '5' is added to ¹/₂ (x - 4)³ ⇒ This means the function f(x) is translated five units up
So the order of transformation that is happening to f(x) = x³ is translation four units to the right, half the y-coordinate, then translate 5 units up.
Answer:
C. (-4x^2)+2xy^2+[10x^2y+(-4x^2y)
Step-by-step explanation:
A. [9-4x2) + (-4x2y) + 10x2y] + 2xy2 : in this polynomial the first term is not a like term, then this is incorrect.
B. 10x2y + 2xy2 + [(-4x2) + (-4x2y)] : in this polynomial, the terms that are grouped, are not like terms, then is incorrect.
C. (-4x2) + 2xy2 + [10x2y + (-4x2y)] ; This polynomial is the right answer because the like terms are grouped.
D. [10x2y + 2xy2 + (-4x2y)] + (-4x2): This polynomial is incorrect because one of the terms that are grouped is not a like term.