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Mandarinka [93]
3 years ago
12

Pls assist if you can.Reasons why hydrogen was chosen as a standard reference to other elements

Chemistry
1 answer:
MrMuchimi3 years ago
4 0

Answer:

See below  

Step-by-step explanation:

  • Hydrogen either reacts with or is formed by reactions with many other elements, so chemists could use it directly to determine their relative masses.
  • Hydrogen has the smallest atomic mass, so it was convenient to give H a relative atomic mass of 1 and assign those of other elements as multiples of this number.

The O = 16 scale became the standard in 1903 and carbon-12 was chosen in 1961.

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Answer:

The statement is false

Explanation:

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Consider the dissolution of AB(s): AB(s)⇌A+(aq)+B−(aq) Le Châtelier's principle tells us that an increase in either [A+] or [B−]
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Answer:

A. 0.000128 M is the solubility of M(OH)2 in pure water.

B. 3.23\times 10^{-6} M is the solubility of M(OH)_2 in a 0.202 M solution of M(NO_3)_2.

Explanation:

A

Solubility product of generic metal hydroxide = K_{sp}=8.45\times 10^{-12}

M(OH)_2\rightleftharpoons M^{2+}+2OH^-

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The expression of a solubility product is given by :

K_{sp}=[M^{2+}][OH^-]^2

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8.45\times 10^{-12}=4S^3

Solving for S:

S=0.000128 M

0.000128 M is the solubility of M(OH)2 in pure water

B

Concentration of M(NO_3)_2 = 0.202 M

Solubility product of generic metal hydroxide = K_{sp}=8.45\times 10^{-12}

M(OH)_2\rightleftharpoons M^{2+}+2OH^-

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So, [M^{2+}]=0.202 M+S

The expression of a solubility product is given by :

K_{sp}=[M^{2+}][OH^-]^2

8.45\times 10^{-12}=(0.202 M+S)(2S)^2

Solving for S:

S=3.23\times 10^{-6} M

3.23\times 10^{-6} M is the solubility of M(OH)_2 in a 0.202 M solution of M(NO_3)_2.

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