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Elenna [48]
3 years ago
12

Which statement is true about the electromagnetic spectrum?

Chemistry
1 answer:
olganol [36]3 years ago
6 0
<span>The statement that tells a fact about the electromagnetic spectrum is the third option. Electromagnetic spectrum contains a spectrum of visible light and a wide array of non-visible forms of radiation. Electromagnetic spectrum is a common term for all frequencies and extended wavelengths of electromagnetic radiation or photons.</span><span />
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Whats the difference between a covalent molecular and covalent network structure​​
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Answer:

Covalent molecular structures are compounds containing molecules with covalent bonds. Covalent network structures are compounds composed of a network structure with covalent bonds between atoms throughout the material.

Explanation:

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1. Salt was added to water and stirred until it completely dissolved. Which
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D

Explanation:

salt molecules evenly distributed after shaking

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Is a pencil falling to the floor anon contact force, a force, or a contact force
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when the top of the pencil moves in one direction, the bottom end on the ground will move in another, but due to the frictional force it will move by a lesser amount, and the center of mass of the pencil will be accelerated in the horizontal direction due to the force of friction

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serg [7]

Which part is your question?

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3 years ago
Sunflower oil contains 0.080 mol palmitic acid (C16H32O2)/mol, 0.060 mol stearic acid (C18H36O2)/mol, 0.27 mol oleic acid (C18H3
Cerrena [4.2K]

Answer:

x_H=0.882

x_N=0.118

Explanation:

In this reactor, oleic and linoleic acid react with hydrogen to form stearic acid. This reactions can be represented by:

Oleic: C_{18}H_{34}O_2 (l) + H_2 (g) \longrightarrow C_{18}H_{36}O_2 (l)

Linoleic: C_{18}H_{32}O_2 (l) + 2 H_2 (g) \longrightarrow C_{18}H_{36}O_2 (l)

Having this reactions in mind, the first thing is to determine the moles of hydrogen required:

<u>Base of caculation: 1 mol of sunflower oil</u>

For oleic acid: n_{Holeic}=\frac{1 mol H_2}{1 mol oleic}*\frac{0.27 mol oleic}{1 mol oil}*\frac{335 mol oil}{hr}

n_{Holeic}=frac{90.45 mol H_2}{hr}

For linoleic acid: n_{Hlinoleic}=\frac{2 mol H_2}{1 mol linoleic}*\frac{0.59 mol linoleic}{1 mol oil}*\frac{335 mol oil}{hr}

n_{Holeic}=frac{395.3 mol H_2}{hr}

n_{Htotal}=\frac{90.45 mol H_2}{hr}+\frac{395.3 mol H_2}{hr}

n_{Htotal}=frac{485.75 mol H_2}{hr}

Applying the excess:

n_{Htotal}=frac{485.75 mol H_2}{hr}*1.65=801.48 mol

Nitrogen: n_N= 801.48 mol*\frac{0.05 mol N}{0.95 mol}

n_N= 42.2 mol N

<u>After the reactions</u>:

n_H=801.48 mol-485.75mol=315.73 mol

and the nitrogen is inert.

Purge stream:

n_total=42.2+315.73 mol=357.93 mol

x_H=\frac{315.73mol}{357.93mol}=0.882

x_N=\frac{42.2mol}{357.93mol}=0.118

4 0
3 years ago
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