3x+3y+6z=9
x+3y+2z=5
3x+12y+12z=18
Step 1: use Eq 2 to solve for x
x+3y+2z=5
x= -3y-2z+5
Step 2: Solve for y unsing Eq 1
3x+3y+6z=9
3y= -3x-6z+9
y= -x-2z+3
Step 3: plug in x= -3y-2z+5 to solve for the value of y
y=-x-2z+3
y= (-1)(-3y -2z +5) - 2z+3
y= 3y+2z-5- 2z+3
-2y= -2
y=1
Step 4: plug y= 1 into the x= equation
x= -3y-2z+5
x= -3(1)-2z+5
x= -2z+2
Step 5:Plug y= 1 and x= -2z+2 into the 3rd equation to solve for z
3x+12y+12z=18
12z= -3(-2z+2)-12(1)+ 18
12z= 6z - 6 - 12 +18
6z= -18+18
6z=0
z=0
Step 6: Plug z in to solve for x
x=-2z+2
x= (-2)(0)+2
x= 2
ANSWER:
x,y,z = 2,1,0
answer choice C
Answer:
True
Step-by-step explanation:
(6³ * 3³)² = 18⁶
Multiply inside the parenthesis.
(18³)² = 18⁶
When you put powers to powers, they multiply, eg:
(x³)⁴ = x³°⁴ = x¹²
18⁶ = 18⁶
True.
Answer: y-intercept
Explanation: A point is classified as (x, y) and in order for this ordered pair to be a y-intercept, we need to have the x-coordinate be 0.
Since the x-coordinate is 0, this is a y-intercept.
Hello from MrBillDoesMath!
Answer: 104x^2 + 166x + 66
Discussion:
The area of a rectangle is given by "length" * "width". For us the formula becomes
(13x + 11) * (8x+6)
or
13x (8x +6) + 11 * (8x + 6) =
(13x * 8x + 13x* 6) + ( 11*8x + 11*6) =
(104x^2 + 78x ) + (88x + 66) =
104x^2 + (78x + 88x) + 66 =
104x^2 + 166x + 66
Thank you,
MrB
