Find the vertex of f(x)= x^2+ 6x + 36 Pls help soon

Mathematics

1 answer:

lutik1710 [3]2 years ago

6 0

Answer:

vertex(-3,27)

Step-by-step explanation:

f(x)= x^2+ 6x + 36 ( a=1,b=6,c=36)

V(h,k)

h=-b/2a=-6/2=-3

k=f(-3)=3²+6(-3)+36

f(-3)=9-18+36=27

vertex(-3,27)

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